这是我的代码,我觉得这应该可以工作。我刚才添加了邮政编码 = str(zipcode),看看它是否可以工作,但它没有,所以我可能会把它拿出来,只让原始邮政编码是一个字符串。我需要它是一个字符串,因为我不希望二进制数实际上相互相加。当我在python shell中初始化函数时,它什么也没返回
def digitConvert(zipcode):
zipcode = str(zipcode)
n = 0
binary = ""
while n < len(zipcode):
if zipcode[n] == 0:
binary = binary + "11000"
n = n + 1
elif zipcode[n] == 1:
binary = binary + "00011"
n = n + 1
elif zipcode[n] == 2:
binary = binary + "00101"
n = n + 1
elif zipcode[n] == 3:
binary = binary + "00110"
n = n + 1
elif zipcode[n] == 4:
binary = binary + "01001"
n = n + 1
elif zipcode[n] == 5:
binary = binary + "01010"
n = n + 1
elif zipcode[n] == 6:
binary = binary + "01100"
n = n + 1
elif zipcode[n] == 7:
binary = binary + "10001"
n = n + 1
elif zipcode[n] == 8:
binary = binary + "10010"
n = n + 1
elif zipcode[n] == 9:
binary = binary + "10100"
n = n + 1
return binary
感谢您的任何帮助!
如果我理解正确,邮政编码是一个整数。这是一个将整数转换为二进制的小 python 函数。默认值是需要 24 位二进制。
def int2bin(n, count=24):
"""returns the binary of integer n, using count number of digits"""
return "".join([str((n >> y) & 1) for y in range(count-1, -1, -1)])
例如,我的邮政编码是60517,所以我会这样做:
>>> print int2bin(60517)
000000001110110001100101
如果我只想要 16 个二进制位:
>>> print int2bin(60517, 16)
1110110001100101
主要问题是zipcode[n]
是一个字符,而不是一个数字,所以它永远不会与数字相等(Python 不会自动转换它们)。您还可以进行许多简化,例如使用 for
循环而不是为字符串编制索引,以及使用字典从十进制数字映射到二进制字符串。
def digitConvert(zipcode):
zipcode = str(zipcode)
digitMap = { '0': '11000', '1': '00011', '2': '00101', ... }
binary = ""
for digit in zipcode:
if digit in digitMap:
binary += digitMap[digit]
return binary
我认为您的代码没有任何问题...除了缩进和检查if
条件。
def digitConvert(zipcode):
zipcode = str(zipcode)
n = 0
binary = ""
while n < len(zipcode):
if zipcode[n] == '0':
binary = binary + "11000"
elif zipcode[n] == '1':
binary = binary + "00011"
elif zipcode[n] == '2':
binary = binary + "00101"
elif zipcode[n] == '3':
binary = binary + "00110"
elif zipcode[n] == '4':
binary = binary + "01001"
elif zipcode[n] == '5':
binary = binary + "01010"
elif zipcode[n] == '6':
binary = binary + "01100"
elif zipcode[n] == '7':
binary = binary + "10001"
elif zipcode[n] == '8':
binary = binary + "10010"
elif zipcode[n] == '9':
binary = binary + "10100"
n = n + 1
return binary
更新:
您可以将整个事情简化为:
def digitConvert(zipcode):
zipcode = str(zipcode)
x = {
"0" : "11000",
"1" : "00011",
"2" : "00101",
"3" : "00110",
"4" : "01001",
"5" : "01010",
"6" : "01100",
"7" : "10001",
"8" : "10010",
"9" : "10100"
}
return "".join(x[i] for i in zipcode if i in x)