根据变量显示PLIST

Question

我目前正在使用下面的代码显示我的plist，但这对我来说似乎效率低下，我认为有一种更干净的方法。

if ([self.title  isEqual: @"How to wear a Kilt"]){
    NSString *path = [[NSBundle mainBundle] pathForResource:@"wearAKilt" ofType:@"plist"];
    // Load the file content and read the data into arrays
    NSDictionary *dict = [[NSDictionary alloc] initWithContentsOfFile:path];
    thumbImg = [dict objectForKey:@"thumbImg"];
    stepLabel = [dict objectForKey:@"stepLabel"];
    descLabel = [dict objectForKey:@"descLabel"];
    }
    // Find out the path of recipes.plist
    else if ([self.title  isEqual: @"How to tie a cravat"]){
        NSString *path = [[NSBundle mainBundle] pathForResource:@"wearACravat" ofType:@"plist"];
        // Load the file content and read the data into arrays
        NSDictionary *dict = [[NSDictionary alloc] initWithContentsOfFile:path];
        thumbImg = [dict objectForKey:@"thumbImg"];
        stepLabel = [dict objectForKey:@"stepLabel"];
        descLabel = [dict objectForKey:@"descLabel"];
    }
    else if ([self.title  isEqual: @"How to wear a sporran"]){
        NSString *path = [[NSBundle mainBundle] pathForResource:@"wearASporran" ofType:@"plist"];
        // Load the file content and read the data into arrays
        NSDictionary *dict = [[NSDictionary alloc] initWithContentsOfFile:path];
        thumbImg = [dict objectForKey:@"thumbImg"];
        stepLabel = [dict objectForKey:@"stepLabel"];
        descLabel = [dict objectForKey:@"descLabel"];
    }

我尝试在 *路径上使用if语句，但这（如预期）会产生undeclared identifier path错误。

if ([self.title  isEqual: @"How to wear a Kilt"]){
    NSString *path = [[NSBundle mainBundle] pathForResource:@"wearAKilt" ofType:@"plist"];
    } else if ([self.title  isEqual: @"How to tie a cravat"]) {
        NSString *path = [[NSBundle mainBundle] pathForResource:@"wearACravat" ofType:@"plist"];
    }

有什么建议？

Answer 1

您的第二位代码，只需：

NSString *path;
if ([self.title  isEqual: @"How to wear a Kilt"]){
    path = [[NSBundle mainBundle] pathForResource:@"wearAKilt" ofType:@"plist"];
} else if ([self.title  isEqual: @"How to tie a cravat"]) {
    path = [[NSBundle mainBundle] pathForResource:@"wearACravat" ofType:@"plist"];
}

您也可以使用字典从传入的字符串映射到关联的文件名...

，例如

NSDicttionary *mapping = @{
    @"How to wear a Kilt" : @"wearAKilt",
    @"How to tie a cravat" : @"wearACravat",
};

可能是静态定义，可能应该考虑本地化。然后：

NSString *name = [mapping objectForKey:self.title];
NSString *path = [[NSBundle mainBundle] pathForResource:name ofType:@"plist"];