我在行中遇到一个错误," self.email =(snapshot.value as!nsdictionary)[" email"] as!string",说它不能抛出它的价值键入" nsnull"。如何解决错误?我以为,由于我有一个函数,可以将所有内容转换为字符串。
struct User {
var email: String!
var uid: String!
var ref: DatabaseReference!
var key: String = ""
init(snapshot: DataSnapshot) {
self.email = (snapshot.value as! NSDictionary)["email"] as! String
self.uid = (snapshot.value as! NSDictionary)["uid"] as! String
self.ref = snapshot.ref
self.key = snapshot.key
}
init(email: String, uid: String) {
self.email = email
self.uid = uid
self.ref = Database.database().reference()
}
func toAnyObject() -> [String: Any] {
return ["email":self.email, "uid":self.uid]
}
}
正如El Captain v2.0指出的那样,不要强制解开值,因为它可能是nil
,您会崩溃。改用if let
:
// if snap has a value, then you can use the value. Otherwise not, you can call an else if you want to.
if let snap = snapshot.value as? [String:Any] {
self.email = snap["email"] as! String
}
,我也会跳过as! String
,而是这样做的,您的Incase不会获得email
值。
if let snap = snapshot.value as? [String:Any], let email = snap["email"] as? String {
// Use email in here now
print(email)
}
因此,如果您有其他要获得的字段,只需将它们添加到if-statement
中。
struct User {
var email: String!
var uid: String!
var ref: DatabaseReference!
var key: String = ""
init(snapshot: DataSnapshot){
self.email = (snapshot.value as! NSDictionary)["email"] as! String
self.uid = (snapshot.value as! NSDictionary)["uid"] as! String
self.ref = snapshot.ref
self.key = snapshot.key
}
init(email: String, uid: String){
if let snap = snapshot.value as? [String:Any] {
// Do not unwrap forcefully, instead use as mentioned below
// so that in case snap["email"] gives null that could be
//handled.
//Also please check that whether you have "firstname" var
//present in not in your code and dictionary both.
self.email = snap["email"] as? String ?? "" //Provide some default value or empty string
}
self.uid = uid
self.ref = Database.database().reference()
}
func toAnyObject() -> [String: Any]{
return ["email":self.email, "uid":self.uid]
}
}