C++无法将对齐的字符串存储在字符串变量中并打印出来

Question

我在字符串对齐方面遇到问题。

我正在尝试打印食品订单的收据，其中食品名称存储在多维数组 (full_menu(、价格(双倍价格(和数量(整数(中。在函数的末尾，这些变量被转换为字符串并附加到字符串变量(订单(中。循环结束后，它被打印出来。请忽略每个订单总价的计算。稍后再做。

#include <iostream>
#include <typeinfo>
#include <iomanip>
using namespace std;
void menu() {
string full_menu [3][6] = {{"A. Chicken",
"1.chicken leg barbecue",
"2.general chicken",
"3.chicken liver abodo",
"4.buffalo wings",
"5.Permesan wings"},
{"B. Soup",
"1.mushroom soup",
"2.cream of corn soup",
"3.hototay soup",
"4.Papaitan soup",
"5.Bulalo soup"},
{"C. Beverages",
"1.coke",
"2.diet coke",
"3.cherry coke",
"4.sprite",
"5.Aqua-Panna"
}};
for(int parent=0; parent<3; parent++)
{
for(int child=0;child<6;child++)
{
cout<<full_menu[parent][child]<<endl;
}
}
//user select the choices and quantity
string orders;
int quantity;
double price;
for (int i =0; i <=i ;i++) {
//food_name//
cout << "Enter your orders(example A1 or b3: ";
int main_menu_number=0;
char main_menu;
int sub_menu = 0;
cin >> main_menu;
if (main_menu == 'a' || main_menu == 'A') {
main_menu_number = 0;
} else if (main_menu == 'b' || main_menu == 'B') {
main_menu_number = 1;
} else if (main_menu == 'c' || main_menu == 'C') {
main_menu_number = 2;
} else if(main_menu=='x'||main_menu=='X'){
break;
}
cin>>sub_menu;
//price//
if (main_menu_number==0&&sub_menu==1){
price=5.00;
} else if(main_menu_number==0&&sub_menu==2) {
price=7.00;
}else if(main_menu_number==0&&sub_menu==3) {
price=5.50;
}else if(main_menu_number==0&&sub_menu==4) {
price=8.00;
}else if(main_menu_number==0&&sub_menu==5) {
price=7.50;
}else if(main_menu_number==1&&sub_menu==1) {
price=4.00;
}else if(main_menu_number==1&&sub_menu==2) {
price=5.50;
}else if(main_menu_number==1&&sub_menu==3) {
price=7.00;
}else if(main_menu_number==1&&sub_menu==4) {
price=8.00;
}else if(main_menu_number==1&&sub_menu==5) {
price=7.50;
}else if(main_menu_number==2&&sub_menu==1) {
price=1.50;
}else if(main_menu_number==2&&sub_menu==2) {
price=1.50;
}else if(main_menu_number==2&&sub_menu==3) {
price=1.50;
}else if(main_menu_number==2&&sub_menu==4) {
price=1.50;
}else if(main_menu_number==2&&sub_menu==5) {
price=0.30;
}
cout<<"Enter quantity :";
cin>>quantity;
orders.append(full_menu[main_menu_number][sub_menu]+"    "+to_string(quantity)+"    "+to_string(price)+"n");
}
cout<<orders;
}

int main()
{
menu();
}

输出为

A. Chicken
1.chicken leg barbecue
2.general chicken
3.chicken liver abodo
4.buffalo wings
5.Permesan wings
B. Soup
1.mushroom soup
2.cream of corn soup
3.hototay soup
4.Papaitan soup
5.Bulalo soup
C. Beverages
1.coke
2.diet coke
3.cherry coke
4.sprite
5.Aqua-Panna
Enter your orders(example A1 or b3:a1
a1
Enter quantity :2
2
Enter your orders(example A1 or b3:c3
c3
Enter quantity :2
2
Enter your orders(example A1 or b3:x
x
1.chicken leg barbecue    2    5.000000
3.cherry coke    2    1.500000

我尝试进行的预期输出是：

1.chicken leg barbecue    2    5.000000
3.cherry coke             2    1.500000

请建议。

Answer 1

使用std::stringstream，以便您可以使用其上的输出运算符，而不是std::string。

您还需要在项目名称之前使用setw()，以使它们的宽度相同。

std::stringstream orders;
...
orders << setw(20) << full_menu[main_menu_number][sub_menu] << setw(5) << quantity << setw(5) << price << "n";

然后，您可以使用以下命令打印最终结果：

cout << orders.str();