我有以下代码:
from pyspark.sql import SQLContext
ctx = SQLContext(sc)
a = ctx.createDataFrame([("1","a",1),("2","a",1),("3","a",0),("4","a",0),("5","b",1),("6","b",0),("7","b",1)],["id","group","value1"])
b = ctx.createDataFrame([("1","a",8),("2","a",1),("3","a",1),("4","a",2),("5","b",1),("6","b",3),("7","b",4)],["id","group","value2"])
c = a.join(b,"id")
c.select("group")
它返回一个错误:
pyspark.sql.utils.AnalysisException: Reference 'group' is ambiguous, could be: group#1406, group#1409.;
问题是c
有两倍相同的列"group"
:
>>> c.columns
['id', 'group', 'value1', 'group', 'value2']
例如,我希望能够做c.select("a.group")
但我不知道如何在进行连接时自动调整列名。
只需删除引号:c.select(a.group)
,它将从数据框中选择group
列a
。