我想读取一个文件，并将每行的内容写入一个维度数组[三][不确定，但很长]
到目前为止，我有以下代码，它能够使用模式匹配器梳理出我正在寻找的输入文件的组件，但是，这卡在输入的第一行，只是一遍又一遍地添加它，如何使输入文件取得进展并每次向数组写入新行。
到目前为止，我的代码如下所示：
public static void main(String[] args) throws IOException
{
BufferedReader br_0 = new BufferedReader(new FileReader("file.txt"));
String line_0;
//while the file is still reading
while ((line_0 = br_0.readLine()) != null)
{
int i = 0;
Pattern p = Pattern.compile("'(.*?)'(?![a-zA-Z])");
//count from zero
String[][] arr = new String[262978][3];
for (int count = 0; count < 262978; count++)
{
Matcher m = p.matcher(line_0);
int j = 0;
while (m.find())
{
arr[i][j++] = m.group(1);
}
i++;
}
}
br_0.close();
}
输入文件如下所示：
'end with'('the playing of the british national anthem', 'hong kong').
'follow at'('the stroke of midnight', 'this').
'take part in'('the ceremony', 'both countries').
'start at about'('# pm', 'the ceremony').
'end about'('# am', 'the ceremony').
'lower'('the british hong kong flag', '# royal hong kong police officers').
'raise'('the sar flag', 'another #').
'leave for'('the royal yacht britannia', 'the #').
'hold by'('the chinese and british governments', 'the handover of hong kong').
'rise over'('this land', 'the regional flag of the hong kong special administrative region of the people 's republic of china').
'cast eye on'('hong kong', 'the world').
'hold on'('schedule', 'the # governments').
'be festival for'('the chinese nation', 'this').
'go in'('the annals of history', 'july # , #').
...
理想情况下，数组索引如下所示：
[0][0] end with
0][1] the playing of the british national anthem
0][2] hong kong
1][0] follow at
][1] the stroke of midnight
1][2] this
2][0] take part in
3][1] the ceremony
][2] both countries
重要的是，数组长度能够容纳非常长的文件，但也容纳短文件。
此时的输出如下所示：
[45993][2] the president of the people 's republic of china he mr jiang zemin
[45994][0] speak at
[45994][1] the ceremony
[45994][2] the president of the people 's republic of china he mr jiang zemin
[45995][0] speak at
[45995][1] the ceremony
[45995][2] the president of the people 's republic of china he mr jiang zemin
[45996][0] speak at
[45996][1] the ceremony
[45996][2] the president of the people 's republic of china he mr jiang zemin
[45997][0] speak at
[45997][1] the ceremony
[45997][2] the president of the people 's republic of china he mr jiang zemin
[45998][0] speak at
[45998][1] the ceremony
[45998][2] the president of the people 's republic of china he mr jiang zemin
[45999][0] speak at
这会
处理第一行262978次。
for (int count = 0; count < 262978; count++)
更好的是：
int count = 0;
String[][] arr = new String[262978][3];
Pattern p = Pattern.compile("'(.*?)'(?![a-zA-Z])");
//while the file is still reading
while ((line_0 = br_0.readLine()) != null) {
Matcher m = p.matcher(line_0);
int j = 0;
while (m.find()) {
arr[count][j++] = m.group(1);
}
count++;
}
br_0.close();
但是，不应使用幻数262978，也不应使用数组。显然，每行最多三个字符串的假设也是不正确的。
将其替换为
List<List<String>> arr = new ArrayList<>();
Pattern p = Pattern.compile("'(.*?)'(?![a-zA-Z])");
//while the file is still reading
while ((line_0 = br_0.readLine()) != null) {
List<String> three = new ArrayList<>();
Matcher m = p.matcher(line_0);
int j = 0;
while (m.find()) {
three.add( m.group(1) );
}
arr.add( three );
}
br_0.close();
要打印，
for( List<String> three: arr ){
for( String s: three ){
System.out.print( s + " " );
}
System.out.println();
}
您正在从此处的文件读取数据： while ((line_0 = br_0.readLine()) != null) ，但是，您在此处使用相同的行进行262978迭代：for (int count = 0; count < 262978; count++) 。
你可以做的，就是用这样的东西替换它：
int i = 0;
Pattern p = Pattern.compile("'(.*?)'(?![a-zA-Z])");
//count from zero
String[][] arr = new String[262978][3];
while (((line_0 = br_0.readLine()) != null) && (i < 262978))
{
Matcher m = p.matcher(line_0);
int j = 0;
while (m.find())
{
arr[i][j++] = m.group(1);
}
i++;
}