从捕获异常策略中抛出自定义异常

Question

是否可以从catch-exception-strategy或任何其他异常策略中抛出我们自己的自定义异常。

我尝试如下：

<catch-exception-strategy doc:name="Catch Exception Strategy">
  <scripting:component doc:name="throw-custom-exception">
    <scripting:script engine="Groovy">
      <![CDATA[throw new org.mycompany.mule.CustomException()]]>
    </scripting:script>
   </scripting:component> 
</catch-exception-strategy>

但最终出现错误：

org.mule.exception.CatchMessagingExceptionStrategy: Failed to dispatch message to error queue after it failed to process

谁能解决这个问题？提前谢谢。

Answer 1

尝试将

<scripting:component doc:name="throw-custom-exception">
    <scripting:script engine="Groovy">
      <![CDATA[throw new org.mycompany.mule.CustomException()]]>
    </scripting:script>
   </scripting:component> 

外面catch-exception-strategy试试...