假设我有一个非常简单的类,带有计算的属性:
class Person {
firstName: string;
lastName: string;
get fuillName(): string {
return this.firstName + ' ' + this.lastName;
}
}
现在我想创建一个类型Person
的对象:
let p: Person = {
firstName: 'John',
lastName: 'Smith'
};
这给了我一个错误:
类型'{firstName:string;lastName:string;}'不能分配"人"。类型'{firstName:string;lastName:string;}'。
嗯?fullName
是仅阅读属性。因此,我遵循了这个问题,并实现了部分初始化器:
constructor(init?: Partial<Person>) {
Object.assign(this, init);
}
相同的错误。我知道我可以这样做:
let p = new Person();
p.firstName = 'John';
p.lastName = 'Smith';
console.debug(p.fullName);
但是是否有速记可以使用JSON语法初始化类?
如果您定义了类别的类:
class Person {
firstName?: string;
lastName?: string;
constructor(values: Object = {}) {
Object.assign(this, values);
}
get fullName(): string {
return this.firstName + ' ' + this.lastName;
}
}
您可以将新用户初始化为以下内容:
let p = new Person({firstName : 'John', lastName: 'Smith'}); //one line, two assignations
console.log(p.fullName);
走得更远:
class Person {
....// as above
set fullName(fullName: string){
let splitName = fullName.split(" ");
this.firstName = splitName[0] || '';
this.lastName = splitName[1] || '';
}
}
let p = new Person()
p.fullName = "Paul Doe";
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