我在playstore上有一个应用程序,在极少数设备上产生以下错误:
java.lang.IllegalArgumentException: width and height must be > 0
at android.graphics.Bitmap.createBitmap(Bitmap.java:829)
at android.graphics.Bitmap.createBitmap(Bitmap.java:808)
at android.graphics.Bitmap.createBitmap(Bitmap.java:775)
at com.my.app.fragments.ImageFragment$MyAsyncTask$1.void run()(SourceFile:209)
at android.os.Handler.handleCallback(Handler.java:745)
at android.os.Handler.dispatchMessage(Handler.java:95)
at android.os.Looper.loop(Looper.java:171)
at android.app.ActivityThread.main(ActivityThread.java:5454)
at java.lang.reflect.Method.invoke(Native Method)
at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:726)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:616)
at de.robv.android.xposed.XposedBridge.main(XposedBridge.java:102)
错误发生在MyAsyncTask
中的onPostExecute
c.drawBitmap(Bitmap.createBitmap(linearLayout.getWidth(), linearLayout.getHeight(), Bitmap.Config.RGB_565), 0, 0, p);
这是我的代码
在我的ImageFragment
和onCreateView
中我这样做
ImageView img = (ImageView) rootView.findViewById(R.id.img);
final LinearLayout view= (LinearLayout) rootView.findViewById(R.id.view);
MyAsyncTask asyncTask= new MyAsyncTask(img, view);
asyncTask.execute(number);
然后在AsyncTask
class MyAsyncTask extends AsyncTask<Integer, Void, Bitmap> {
private final WeakReference<ImageView> imageViewReference;
private LinearLayout linearLayout;
public MyAsyncTask(ImageView imageView, LinearLayout linearLayout) {
imageViewReference = new WeakReference<>(imageView);
this.linearLayout = linearLayout;
}
// Decode image in background.
@Override
protected Bitmap doInBackground(Integer... params) {
// Code skipped
return bitmap;
}
@Override
protected void onPostExecute(Bitmap bitmap) {
if (bitmap != null) {
final ImageView imageView = imageViewReference.get();
if (imageView != null) {
imageView.setImageBitmap(bitmap);
blurred = CommonUtils.fastblur(bitmap, 0.2f, 20);
final Bitmap resultBitmap = Bitmap.createBitmap(blurred.getWidth(), blurred.getHeight(), Bitmap.Config.ARGB_8888);
final Canvas c = new Canvas(resultBitmap);
c.drawBitmap(blurred, 0, 0, null);
final Paint p = new Paint();
p.setAlpha(127);
linearLayout.post(new Runnable() {
@Override
public void run() {
c.drawBitmap(Bitmap.createBitmap(linearLayout.getWidth(), linearLayout.getHeight(), Bitmap.Config.RGB_565), 0, 0, p);
// Rest code skipped
}
});
}
}
}
}
在阅读了许多关于这个问题的stackoverflow帖子后,我发现如果视图尚未准备好,则会发生这种情况,因此它应该与视图的post方法一起使用,并带有自己的runnable。但我不明白为什么它仍然在某些设备上导致这个错误,即Samsung
。有人知道如何解决这个问题吗?任何建议都将不胜感激。谢谢! !
您的任务在此设备上运行太快,LinearLayout
仍未布局。您可以使用ViewTreeObserver
:
ViewTreeObserver vto = linearLayout.getViewTreeObserver();
vto.addOnGlobalLayoutListener(new OnGlobalLayoutListener() {
@Override
public void onGlobalLayout() {
linearLayout.getViewTreeObserver().removeGlobalOnLayoutListener(this);
int width = linearLayout.getMeasuredWidth();
int height = linearLayout.getMeasuredHeight();
c.drawBitmap(Bitmap.createBitmap(width, height, Bitmap.Config.RGB_565), 0, 0, p);
// Rest code skipped
}
});