在nodejs中读取ajax数据

Question

我正在从客户端进行ajax调用。想要将数据（城市值）传递到客户端。当我尝试在服务器端访问值时，我无法访问其值。这是代码

服务器：

var express = require("express"),
http = require("http"),
bodyParser= require("body-parser"),
yelp = require("yelp"),
app;
// Create our Express-powered HTTP server
/ and have it listen on port 3000
app = express();
http.createServer(app).listen(3000);

// set up a static file directory to use for default routing
app.use(express.static(__dirname));
// set up our routes
// for user login
app.get("/yelp", function (req, res) {
var city = req.query.city;
var yelp = require("yelp").createClient({
consumer_key: "xyz", 
consumer_secret: "xyz",
token: "xyz",
token_secret: "xyz"
});
console.log("city="+city);
// See http://www.yelp.com/developers/documentation/v2/search_api
yelp.search({term: "restaurants", location:"fullerton" , limit: 5 },    function  (error, data) {
console.log(error);
res.format({
    'application/jsonp': function(){
res.send('yelp('+JSON.stringify(data)+');');
}
});
});
});

客户端 ajax 调用函数：

var main = function () {
"use strict";
var $button= $("#search");   
$button.on("click",function(){
var input_city= $("#city").val();
$.ajax({
        type: "GET",
        url: "/yelp",
        data: JSON.stringify({city :input_city }),
        jsonpCallback: "yelp",
        contentType: "application/jsonp; charset=utf-8",
        dataType: "jsonp"
       /* success: function(msg){
            console.log("success called");
            var $result = $.parseJSON(msg);
            console.log($result.businesses[0].name);
            $('#list').append("<div>"+$result.businesses[0].name+"    </div>");
        },
        error: function (errormessage){
            console.log("error called");
            $('#list').append(errormessage);
    }*/
    })
    .done(function (data,status){
  $('#list').html("");
    var i = 0;
   for(i=0; i < data.businesses.length; i++)
   {
    $('#list').append("<div class='business'>");
    $('#list').append("<div class='business_name'>");
     $('#list').append(data.businesses[i].name);
    $('#list').append("</div>");
     $('#list').append("<div class='business_address'>");
     $('#list').append(data.businesses[i].location.display_address);
     $('#list').append("</div>");
    $('#list').append("<div class='business_phone'>");
     $('#list').append(data.businesses[i].phone);
    $('#list').append("</div>");
    $('#list').append("<div class='business_rating'>");
     $('#list').append(data.businesses[i].rating);
    $('#list').append("</div>");
    $('#list').append("</div>");
   }
    })
    .fail(function (data, status){
    console.log("fail called");
    console.log(data);
    console.log(status);
});

            });
};

服务器端控制台的输出 城市 = 未定义

Answer 1

您的服务器实际上期望city是一个查询字符串。在客户端，执行以下操作：

    url: "/yelp?city=" + input_city,

并删除data:...行。