对于一项课程作业,我必须创建一个类似Facebook的应用程序。
目前,我正在"时间线"页面上工作,并努力解决所需的SQL查询的复杂性。
我想要的结果是在单个表格中显示帖子和回复,并对或进行分组或排序,以便回复位于相应帖子下方
eg post_id text
1 First post
1 Response 1 to post 1
1 Response 2 to post 1
2 Second post
2 Response 1 to post 2
2 Response 2 to post 2
数据库架构如下:
create or replace type post_obj as object (
post_id number,
post_text varchar2(500),
user_posted_by ref user_obj,
post_date timestamp,
map member function get_postid return number) not final;
create table post_obj_tbl of post_obj;
create or replace type response_obj as object (
response_id number,
response_text varchar2(500),
post_details ref post_obj,
user_posted_by ref user_obj,
response_date timestamp,
map member function get_responseid return number) not final;
create table response_obj_tbl of response_obj;
到目前为止,我已经设法让两个表连接起来,以便我得到一个显示帖子和响应的表格,但它会自动按用户 ID 分组。下面是查询:
SELECT p_tbl.user_posted_by.username, p_tbl.post_text, p_tbl.post_date
FROM post_obj_tbl p_tbl
WHERE
p_tbl.user_posted_by.user_id = (
SELECT u_tbl.user_id
FROM user_obj_tbl u_tbl
WHERE u_tbl.username = (select V('APP_USER') from DUAL) )
OR
p_tbl.user_posted_by.user_id in (
SELECT f_tbl.friend_id
FROM friends_obj_tbl f_tbl
WHERE f_tbl.user_id = (
SELECT u_tbl.user_id
FROM user_obj_tbl u_tbl
WHERE u_tbl.username = (select V('APP_USER') from DUAL) )
)
UNION
SELECT r_tbl.user_posted_by.username, r_tbl.response_text, r_tbl.response_date
FROM response_obj_tbl r_tbl, post_obj_tbl p_tbl
WHERE r_tbl.post_details.post_id = p_tbl.post_id;
我真的希望这是有道理的...弄乱了我的脑袋!任何帮助非常感谢:)
首先,为什么要创建对象表?通常的方法是创建这样的表:
create table post_obj (
post_id number,
post_text varchar2(500),
user_posted_by number,
post_date timestamp);
使用这样的表要容易得多,尤其是在 APEX 中。
关于查询。我将采取一部分:
SELECT p_tbl.user_posted_by.username, p_tbl.post_text, p_tbl.post_date
FROM post_obj_tbl p_tbl
WHERE
p_tbl.user_posted_by.user_id = (
SELECT u_tbl.user_id
FROM user_obj_tbl u_tbl
WHERE u_tbl.username = (select V('APP_USER') from DUAL) )
它可以转换为:
SELECT p_tbl.user_posted_by.username, p_tbl.post_text, p_tbl.post_date
FROM post_obj_tbl p_tbl,
user_obj_tbl u_tbl
WHERE p_tbl.user_posted_by = u_tbl.user_id
AND u_tbl.username = V('APP_USER')