将对象与对象进行比较

Question

>我有那个对象和简单的对象

public positions = {
    reading: {
        left: "0px",
    },
    writing: {
        left: "0px",
    },
    speaking: {
        left: "0px",
    },
    listening: {
        left: "0px",
    },
};

我需要检查某些"left"属性是否相同，以及它们是否将"top"属性添加到其中一个属性。例如，如果我有这样的对象：

public positions = {
    reading: {
        left: "10px",
    },
    writing: {
        left: "20px",
    },
    speaking: {
        left: "20px",
    },
    listening: {
        left: "7px",
    },
};

修鲁德改成这样：

public positions = {
    reading: {
        left: "10px",
    },
    writing: {
        left: "20px",
    },
    speaking: {
        left: "20px",
        top: "10px"
    },
    listening: {
        left: "7px",
    },
};

我需要最简单的方法来做到这一点。

Answer 1

也许是这个？

const positions = {
    reading: {
        left: "0px",
    },
    writing: {
        left: "0px",
    },
    speaking: {
        left: "0px",
    },
    listening: {
        left: "0px",
    },
};
const positions2 = {
    reading: {
        left: "0px",
    },
    writing: {
        left: "0px",
    },
    speaking: {
        left: "0px",
    },
    listening: {
        left: "0px",
    },
};
for (var key in positions) {
  if (positions2[key].left == positions[key].left) {
    positions2[key].top = '10px'
  }
}
console.log(positions2)