如何使用 R 在单个图中绘制数据帧中变量的散点图和所有其他变量?

Question

我尝试在GGally中使用ggpair来绘制散点图。但它绘制了每个变量 与所有其他变量。我想将特定变量的散点图与数据帧中的所有其他变量绘制，并显示每个散点图的相关值。 请帮助我。 提前谢谢。

Answer 1

答案真的是一个谷歌搜索，但在这里。

library(ggplot2)
library(grid)
# google search: "multiplot ggplot2"
# http://www.cookbook-r.com/Graphs/Multiple_graphs_on_one_page_(ggplot2)/
multiplot <- function(..., plotlist=NULL, file, cols=1, layout=NULL) {

# Make a list from the ... arguments and plotlist
plots <- c(list(...), plotlist)
numPlots = length(plots)
# If layout is NULL, then use 'cols' to determine layout
if (is.null(layout)) {
# Make the panel
# ncol: Number of columns of plots
# nrow: Number of rows needed, calculated from # of cols
layout <- matrix(seq(1, cols * ceiling(numPlots/cols)),
ncol = cols, nrow = ceiling(numPlots/cols))
}
if (numPlots==1) {
print(plots[[1]])
} else {
# Set up the page
grid.newpage()
pushViewport(viewport(layout = grid.layout(nrow(layout), ncol(layout))))
# Make each plot, in the correct location
for (i in 1:numPlots) {
# Get the i,j matrix positions of the regions that contain this subplot
matchidx <- as.data.frame(which(layout == i, arr.ind = TRUE))
print(plots[[i]], vp = viewport(layout.pos.row = matchidx$row,
layout.pos.col = matchidx$col))
}
}
}
# some dummy data
x <- as.data.frame(matrix(rnorm(100), 10, 10))
# plot the first variable against all others
plotList <- list()
for (i in 1:9) {
plotList[[i]] <- ggplot(data = x, aes_(x = x[, 1], y = x[, i+1])) + geom_point() + xlab("x") + ylab("y")
}
# actually draw the multiplot
multiplot(plotlist = plotList, cols = 3)