我有一个在Shopify网站上使用的代码。基本上有3个送货选项,其中一个是星期六的送货,除了选择该收音机时,除了星期六以外的所有天数。
<div class="delivery-radio">
<h3>1. Choose your delivery type:</h3>
<input type="radio" name="attributes[delivery-type]" value="Standard" checked> Standard - Delivery by 6pm (£4.95)<br>
<input type="radio" name="attributes[delivery-type]" value="Pre 12" id="pre_12"> Express - Delivery by 12pm (£6.25)<br>
<input type="radio" name="attributes[delivery-type]" value="saturday" id="saturday"> Saturday - Delivery by 6pm (£6.95)
</div>
<div style="width:300px; clear:both;">
<h3>2. Pick a delivery date:</h3>
<p>
<input id="date" type="text" name="attributes[date]" value="{{ cart.attributes.date }}" required readonly="readonly" /> <span id="calendar_click" class="glyphicon glyphicon-calendar" aria-hidden="true"></span>
</p>
</div>
我需要的是一个函数,该函数不会破坏我当前的代码,从而禁用英国银行假期。我已经看到可以通过添加日期并禁用它们来手动完成此操作,但是我尝试过的一切都无法正常工作或破坏我当前的代码。
这是我的代码的片段,如果任何jQuery/javascript guru可以帮助您,因为我在这个领域不太先进。
jQuery(function() {
$('input[name="attributes[delivery-type]"]').on('click', function(){
$("#date").datepicker("destroy");
if($(this).val() == "saturday") {
$("#date").datepicker({
dateFormat: 'dd-mm-yy',
minDate: +1,
maxDate: '+2M',
beforeShowDay: function(date){ return [date.getDay() == 6 || date.getDay() == 6,""]}
});
} else {
$("#date").datepicker(
{
dateFormat: 'dd-mm-yy',
minDate: +1,
maxDate: '+2M',
beforeShowDay: function(date) {
var day = date.getDay();
return [(day != 0 && day != 1), ''];
}
});
}
});
$("#date").datepicker(
{
dateFormat: 'dd-mm-yy',
minDate: +1,
maxDate: '+2M',
beforeShowDay: function(date) {
var day = date.getDay();
return [(day != 0 && day != 1), ''];
}
});
});
datesDisabled
似乎是bootstrap datepicker的功能。
您可以将支票添加到beforeShowDay
函数,我将其与不同的部分分开,并根据需要使用变量。
翻译从
的星期六交付beforeShowDay: function(date){ return [date.getDay() == 6 || date.getDay() == 6,""]}
beforeShowDay: saturdayOnly
和您的默认值
beforeShowDay: function(date) {
var day = date.getDay();
return [(day != 0 && day != 1), ''];
}
beforeShowDay: notSunMon
然后添加以下两个选项的处理:
````
function saturdayOnly (date) {
return dayStatus (date, array(0,1,2,3,4,5));
}
function notSunMon (date) {
return dayStatus (date, array(0,1));
}
var disabledDates = ["22-03-2018", "29-03-2018", "03-04-2018"];
function dayStatus (date, disableDays) {
//Sat = 6, Sun = 0
var dayNumber = date.getDay();
if (disableDays.indexOf(dayNumber) !== -1) {
return [false, ' disabledDay'];
}
var compareDate = formatDate(date);
if (disabledDates.indexOf(compareDate) !== -1) {
return [false, ' disabledDate'];
}
return [true, ' availableDay'];
}
function formatDate(date) {
var dd = date.getDate().toString();
var mm = (date.getMonth() + 1).toString(); // getMonth() is zero-based
var yyyy = date.getFullYear().toString();
//format as dd-mm-yyyy - make sure Disabled Dates match this format
return (dd[1] ? dd : "0" + dd[0]) + "-" + (mm[1] ? mm : "0" + mm[0]) + "-" + yyyy;
}
````
这使用一个函数来格式化日期,以确保它们都正确,并添加CSS类。有关如何实现这些内容,请参见JSFIDDLE。
只是注释,days !=0 && day != 1
检查"不是星期日/星期一"
使用JSFiddle尝试一下:https://jsfiddle.net/vreemt/sbrtyvoz/
默认情况下,我已经通过保持周六和周日的送货来保留daysofweekdisabled:[0,6],对于周六的交货选项,我将其保留为-Weekeekdisabled -daysofweekdisabled:[0,1,2,2,[0,1,2,3,4,5]。银行假期列表位于datesdisabled中。头脑和麦克斯特(Maxdate(也是起步和终结。
<div class="delivery-radio">
<h3>1. Choose your delivery type:</h3>
<input type="radio" name="attributes[delivery-type]" value="Standard" checked> Standard - Delivery by 6pm (£4.95)<br>
<input type="radio" name="attributes[delivery-type]" value="Pre 12" id="pre_12"> Express - Delivery by 12pm (£6.25)<br>
<input type="radio" name="attributes[delivery-type]" value="saturday" id="saturday"> Saturday - Delivery by 6pm (£6.95)
</div>
<div style="width:300px; clear:both;">
<h3>2. Pick a delivery date:</h3>
<p>
<input id="date" type="text" name="attributes[date]" value="{{ cart.attributes.date }}" required readonly="readonly" /> <span id="calendar_click" class="glyphicon glyphicon-calendar" aria-hidden="true"></span>
</p>
</div>
<script>
$(document).ready(function(){
var maxDate = getAdjustedDate(+60);
var minDate = getAdjustedDate(+1);
var tempDt = new Date();
console.log("today: "+tempDt.getDate());
console.log("minDate: "+minDate);
console.log("maxDate: "+maxDate);
$('input[name="attributes[delivery-type]"]').on('click', function(){
$("#date").datepicker("destroy");
if($(this).val() === "saturday") {
$("#date").datepicker({
format: 'dd/mm/yyyy',
startDate: minDate,
endDate: maxDate,
daysOfWeekDisabled: [0,1,2,3,4,5],
datesDisabled: ['30/03/2018','02/04/2018','07/05/2018','28/05/2018','27/08/2018','25/12/2018','26/12/2018']
});
} else {
$("#date").datepicker(
{
format: 'dd/mm/yyyy',
startDate: minDate,
endDate: maxDate,
daysOfWeekDisabled: [0,6],
datesDisabled: ['30/03/2018','02/04/2018','07/05/2018','28/05/2018','27/08/2018','25/12/2018','26/12/2018']
});
}
});
$("#date").datepicker(
{
format: 'dd/mm/yyyy',
startDate: minDate,
endDate: maxDate,
daysOfWeekDisabled: [0,6],
datesDisabled: ['30/03/2018','02/04/2018','07/05/2018','28/05/2018','27/08/2018','25/12/2018','26/12/2018']
});
});
var getAdjustedDate = function (adjustment) {
var today = new Date();
today.setDate(today.getDate() + adjustment);
var dd = today.getDate()-1;
var mm = today.getMonth()+1; //January is 0!
var yyyy = today.getFullYear();
if(dd<10){
dd='0'+dd;
};
if(mm<10){
mm='0'+mm;
};
return dd+'/'+mm+'/'+yyyy;
};
</script>