UIButton在ios7的openURL之后不工作

Question

我有多个共享按钮调用openURL。按下第一个按钮后，它会打开Safari进行分享，当我回到我的应用程序时，所有按钮都不起作用。(只支持iOS 7.1，但iOS 8也可以)

下面是我的代码:

- (IBAction)btnFacebook_TouchUpInSide:(id)sender
{
    NSLog(@"Touch FaceBook");
    NSString *shareUrl = @"some url";
    NSString *shareText = @"some text";
    NSString *shareDescription = @"some text";
    NSString *sharePictureUrl = @"some text";
    NSString *sharingURL = [self encodeURL:[NSString stringWithFormat:@"https://www.facebook.com/dialog/feed?app_id=388711667988471&display=page&caption=%@&description=%@&picture=%@&link=%@&redirect_uri=%@", shareText, shareDescription, sharePictureUrl, shareUrl, shareUrl]];
    if([[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:sharingURL]])
    {
        [[UIApplication sharedApplication] openURL:[NSURL URLWithString:sharingURL]];
    }
}
- (IBAction)btnTwitter_TouchUpInSide:(id)sender
{
    NSLog(@"Touch Twitter");
    NSString *shareUrl = @"some url";
    NSString *shareText = @"some text";
    NSString *sharingURL = [self encodeURL:[NSString stringWithFormat:@"twitter://post?message=%@", [self encodeURL:[NSString stringWithFormat:@"%@ %@", shareUrl, shareText]]]];
    if([[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:sharingURL]])
    {
        [[UIApplication sharedApplication] openURL:[NSURL URLWithString:sharingURL]];
    }
    else
    {
        NSLog(@"Open web to share twitter!");
        sharingURL = [NSString stringWithFormat:@"https://twitter.com/intent/tweet?url=%@&text=%@&count=none/",[self encodeURL:shareUrl],[self encodeURL:shareText]];
        if([[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:sharingURL]])
        {
            [[UIApplication sharedApplication] openURL:[NSURL URLWithString:sharingURL]];
        }
    }
}
- (IBAction)btnPinterest_TouchUpInSide:(id)sender
{
    NSLog(@"Touch Pinterest");
    NSString *shareUrl = @"some url";
    NSString *shareText = @"some text";
    NSString *shareMedia = @"some text";
    NSString *sharingURL = [self encodeURL:[NSString stringWithFormat:@"pinit12://pinterest.com/pin/create/link/?url=%@&media=%@&description=%@", shareUrl, shareMedia, shareText]];
    if([[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:sharingURL]])
    {
        [[UIApplication sharedApplication] openURL:[NSURL URLWithString:sharingURL]];
    }
    else
    {
        NSLog(@"Open web to share Pinterest!");
        sharingURL = [self encodeURL:[NSString stringWithFormat:@"https://www.pinterest.com/pin/create/link/?url=%@&media=%@&description=%@", shareUrl, shareMedia, shareText]];
        if([[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:sharingURL]])
        {
            [[UIApplication sharedApplication] openURL:[NSURL URLWithString:sharingURL]];
        }
    }
}
- (IBAction)btnLinkedIn_TouchUpInSide:(id)sender
{
    NSLog(@"Touch LinkedIn");
    NSString *shareUrl = @"some url";
    NSString *shareTitle = @"some text";
    NSString *shareSummary = @"some text";
    NSString *shareSource = @"some text";
    NSString *sharingURL = [NSString stringWithFormat:@"https://www.linkedin.com/shareArticle?mini=true&url=%@&title=%@&summary=%@&source=%@",[self encodeURL:shareUrl],[self encodeURL:shareTitle],[self encodeURL:shareSummary],[self encodeURL:shareSource]];
    if([[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:sharingURL]])
    {
        [[UIApplication sharedApplication] openURL:[NSURL URLWithString:sharingURL]];
    }
}

谢谢。

Answer 1

试试这个:

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:sharingURL]];

而不是:

if([[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:sharingURL]])
    {
        [[UIApplication sharedApplication] openURL:[NSURL URLWithString:sharingURL]];
    }

将openURL移出if块canOpenURL