创建JSON对象或字符串

Question

可以在c#中使用字符串初始化JSON对象吗?

like: "Person": [{"age":"42","name":"John"}]

作为object JsonData = "Person": [{"age":"42","name":"John"}];

? ?

所以我可以把这个JSON对象直接给DatacontractJSONSerializer

我可以从中得到数据!

---

        List<Person> people = new List<Person>{
                   new Person{age  = 1, name  = "Scott"},
                   new Person{age = 2, name  = "Bill"}
                   };


            string jsonString = ExtensionMethods.JSONHelper.ToJSON(people);

         }
    }
}
namespace ExtensionMethods
{
    public static class JSONHelper
    {
        public static string ToJSON(this object obj)
        {
            JavaScriptSerializer serializer = new JavaScriptSerializer();
            return serializer.Serialize(obj);
        }
        public static string ToJSON(this object obj, int recursionDepth)
        {
            JavaScriptSerializer serializer = new JavaScriptSerializer();
            serializer.RecursionLimit = recursionDepth;
            return serializer.Serialize(obj);
        }
    }
}

string jsonString = ExtensionMethods.JSONHelper.ToJSON(people);

给出一个字符串:[{},{}]

空数据结构，有什么想法吗?

Answer 1

对于扩展方法，您希望将您的方法修补到您打算调用该方法的类型上。在这种情况下，IEnumerable是添加您想要在List上使用的方法的好地方:

public class Person {
  public int age { get; set; }
  public string name { get; set; }
}
public static class JSONHelper {
  public static string ToJSON(this IEnumerable obj) {
    return new JavaScriptSerializer().Serialize(obj);
  }
}
void Main() {
  List<Person> people = new List<Person> {
    new Person() { age = 1, name = "Scott" },
    new Person() { age = 2, name = "Bill" }
  };
  // [{"age":1,"name":"Scott"},{"age":2,"name":"Bill"}]
  string json = people.ToJSON();
}

重要的区别在于，您应该针对定义它的类型的变量使用扩展方法。你不应该直接引用扩展方法