使用海绵城堡库在ECDH中生成密钥对

Question

我是台湾的学生。我正在学习如何在Android上编程。但是我有一个问题关于使用海绵城堡库在ECDH中生成密钥对。当我启动应用程序时，android系统显示应用程序已停止。

这是我的代码和我的导入

public class MainActivity<ECParams> extends Activity {
    String msg,Test;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        Button generator= (Button) findViewById(R.id.key_pair_generator);
        generator.setOnClickListener(ECkeyPairGenerator);
    }
    @Override
    public boolean onCreateOptionsMenu(Menu menu) {
        // Inflate the menu; this adds items to the action bar if it is present.
        getMenuInflater().inflate(R.menu.main, menu);
        return true;
    }
    private Button.OnClickListener ECkeyPairGenerator = new Button.OnClickListener()
    {
        public void onClick(View v) {
            KeyPairGenerator kpg=null;
            ECGenParameterSpec ecParamSpec = new ECGenParameterSpec("secp224k1");
            try {
                kpg = KeyPairGeneratorSpi.getInstance("ECDH", "SC");
            } catch (NoSuchAlgorithmException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } catch (NoSuchProviderException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            try {
                kpg.initialize(ecParamSpec);
            } catch (InvalidAlgorithmParameterException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            KeyPair kpair=kpg.generateKeyPair();
            msg="pp";
            ShowMsg();
        }
    };
    public static String byteArrayToHexString(byte b[]) {
        StringBuffer s = new StringBuffer();
        int LEN = b.length;
        if (b.length != LEN)
            throw new RuntimeException("byteArrayToHexString() " +
                                       "wrong argument length (!="+LEN);
        for (int j = 0; j < b.length; j++) {
            s.append(Integer.toHexString((int)((b[j]>>4)&0x0f)));
            s.append(Integer.toHexString((int)(b[j]&0x0f)));
        }        
        return new String(s);
    }
    public void ShowMsg(){
        Intent intent = new Intent();
        intent.setClass(MainActivity.this, Show.class);
        Bundle bundle = new Bundle();
        bundle.putString("Show", msg);
        intent.putExtras(bundle); 
        startActivity(intent);
    }
}

请帮。

Answer 1

我解决了这个问题。它需要通过一种新的方式添加提供者。这样的。

    static {Security.insertProviderAt(new org.spongycastle.jce.provider.BouncyCastleProvider(), 1);}

和生成密钥对的代码:

    try {
            ECGenParameterSpec ecParamSpec = new ECGenParameterSpec("secp224k1");
            KeyPairGenerator kpg = KeyPairGenerator.getInstance("ECDH","SC");
            kpg.initialize(ecParamSpec);
            KeyPair kpair=kpg.generateKeyPair();
            pkey=kpair.getPublic();
            skey=kpair.getPrivate();
        }catch(Exception e){e.printStackTrace();}

谢谢