如何从谷歌 API 获取 lat ,长,我有一些代码它工作得很好,但有时它给了我们,即使我在印度,英国的价值。
String surl = "http://mobilemaps.clients.google.com/glm/mmap";
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(surl);
httppost.setEntity(new MyCellIDRequestEntity(shortcid, lac));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
DataInputStream dis = new DataInputStream(entity.getContent());
// Read some prior data
dis.readShort();
dis.readByte();
// Read the error-code
int errorCode = dis.readInt();
System.err.println("Error Code iss::" + errorCode);
int api = myPrefs2.getInt("api", 0);
if (errorCode == 0)
{
lat = (double) dis.readInt() / 1000000D;
lng = (double) dis.readInt() / 1000000D;
System.err.println("lattitude::" + Double.toString(lng) + "::long::" + Double.toString(lat));
} else {
// System.err.println("Wrong Error Code");
}
} catch (Exception e) {
}
只需通过链接即可获得用户位置的完整地址。
试试这个 -
从活动调用函数:
String location_name = getmylocation(latitude+","+longitude)
getMyLocation() 方法将提供您的位置字符串 -
public String getmylocation(String value)
{
JSONObject json = JSONfunctions.getJSONfromURL("http://maps.googleapis.com/maps/api/geocode/json?latlng="+value+"&sensor=true");
try{
JSONArray georesult = json.getJSONArray("results");
JSONObject e = georesult.getJSONObject(0);
String result = e.getString("address_components");
JSONArray jArray1 = new JSONArray(result);
JSONObject json_data=jArray1.getJSONObject(3);
loc = json_data.getString("long_name");
}catch(JSONException e)
{
e.printStackTrace();
}
return loc;
}
JSON函数.java
package com.sample.getcurrentlocation;
import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONException;
import org.json.JSONObject;
import android.util.Log;
public class JSONfunctions {
public static JSONObject getJSONfromURL(String url){
InputStream is = null;
String result = "";
JSONObject jArray = null;
//http post
try{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(url);
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
}catch(Exception e){
Log.e("log_tag", "Error in http connection "+e.toString());
}
//convert response to string
try{
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "n");
}
is.close();
result=sb.toString();
}catch(Exception e){
Log.e("log_tag", "Error converting result "+e.toString());
}
try{
jArray = new JSONObject(result);
}catch(JSONException e){
Log.e("log_tag", "Error parsing data "+e.toString());
}
return jArray;
}
}
您可以使用String location_name
简单地查看位置 而且,不要忘记添加所需的权限 -
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION"></uses-permission>
<uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION"></uses-permission>