Zend框架中的数据库连接

我是ZF的新手。我把我的application.ini编码在这里：

[development]
includePaths.library = APPLICATION_PATH "/../library"
bootstrap.path = APPLICATION_PATH "/Bootstrap.php"
bootstrap.class = "Bootstrap"
appnamespace = "Application"
resources.frontController.controllerDirectory = APPLICATION_PATH "/controllers"
resources.frontController.params.displayExceptions = 0
resources.view.encoding = "utf-8"
resources.layout.layoutPath = APPLICATION_PATH "/layouts/scripts"

phpSettings.display_startup_errors = 1
phpSettings.display_errors = 1
phpSettings.display_startup_errors = 1
phpSettings.display_errors = 1
resources.frontController.params.displayExceptions = 1
resources.DB.adapter            = "pdo_mysql"
resources.DB.params.host        = "localhost"
resources.DB.params.username    = "root"
resources.DB.params.password    = ""
resources.DB.params.dbname      = "xyz"

这是我的index.php

              defined('APPLICATION_PATH')
              || define('APPLICATION_PATH', realpath(dirname(__FILE__) . '/../application'));
          // Define application environment
          defined('APPLICATION_ENV')
              || define('APPLICATION_ENV', (getenv('APPLICATION_ENV') ? getenv('APPLICATION_ENV') : 'development'));
          // Ensure library/ is on include_path
          set_include_path(implode(PATH_SEPARATOR, array(
              realpath(APPLICATION_PATH . '/../library'),
              get_include_path(),
          )));
          /** Zend_Application */
          require_once 'Zend/Application.php';
          // Create application, bootstrap, and run
          $application = new Zend_Application(
              APPLICATION_ENV,
              APPLICATION_PATH . '/configs/application.ini'
          );
          $application->bootstrap()->run();

这是我的引导程序.php

class Bootstrap extends Zend_Application_Bootstrap_Bootstrap{
protected function _initDoctype(){
    $this->bootstrap('view');
    $view = $this->getResource('view');
    $view->doctype(Zend_View_Helper_Doctype::HTML5);
   }
}

现在，首先我像这个一样连接

    $params = array('host'         => 'localhost',
            'username'  => 'root',
            'password'    => '',
            'dbname'        => 'xyz'
          );
   $DB      = new Zend_Db_Adapter_Pdo_Mysql($params);
      $DB->setFetchMode(Zend_Db::FETCH_OBJ);
      Zend_Registry::set('DB',$DB);

在后来的查询中，我使用它来检索记录：

$registry = Zend_Registry::getInstance();  
$DB = $registry['DB']; and than my query

既然我已经改变了我的设置，包括bootstrap和application.ini，如何实现和我一样的效果？因为在我的应用程序中，一切都是这样的。。

现在我得到了这个错误。

注意：未定义的索引：中的DB

C： 第59行的\examplep\htdocs\xyz\application\controllers\LoginController.php
致命错误：在第64行中的C:\examplep\htdocs\xyz\application\controllers\LoginController.php中的非对象上调用成员函数select（）

59号线为

 $registry = Zend_Registry::getInstance();  
 $DB = $registry['DB'];

64号线为

 $select = $DB->select()
     ->from(array('p' => 'phone_service'))
     ->join(array('u' => 'user_preferences'), 'u.phone_service_id = p.phone_service_id')
     ->where('u.user_preferences_name = ?', 'is_user_package_active')
     ->where('p.user_id = ?', $user_id);

已编辑

if($result->isValid()){
$data = $authAdapter->getResultRowObject(null,'password');
$auth->getStorage()->write($data);
$this->_redirect('/login/controlpannel');}

现在我的查询在这里找不到$user_id

$data = Zend_Auth::getInstance()->getStorage()->read();  
$user_id = $data->user_id;
  $DB = Zend_Db_Table_Abstract::getDefaultAdapter();
 $select = $DB->select()
     ->from(array('p' => 'phone_service'))
     ->join(array('u' => 'user_preferences'), 'u.phone_service_id = p.phone_service_id')
     ->where('u.user_preferences_name = ?', 'is_user_package_active')
     ->where('p.user_id = ?', $user_id);

这就是为什么我得到这个错误

注意：试图在我的.phtml文件中获取非对象的属性