我正在GAE
中实现SOAP
web服务。由于GAE
不支持JAX-WS
,所以我选择了这种方式,基本上就是自己从servlet构建soap请求和响应。
一切都很好,但我如何才能在http://myurl/MyService?wsdl
中返回wsdl描述?
我想我必须实现servlet的GET
方法,但如何实现呢?
我附上了一个工作实现。请注意,它是基于Servlet 3.0规范的。如果您使用的是2.5,注释将无法工作。
import java.io.FileInputStream;
import java.io.IOException;
import java.util.Enumeration;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
@WebServlet(name="MyWSServlet", urlPatterns={"/MyService"})
public class MyWSServlet extends HttpServlet {
private static final long serialVersionUID = 3605874163075522777L;
@Override
protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
boolean requestForWSDL = false;
Enumeration<String> params = req.getParameterNames();
while (params.hasMoreElements()) {
if ("wsdl".equalsIgnoreCase(params.nextElement())) {
requestForWSDL = true;
}
}
if (requestForWSDL) {
FileInputStream wsdlInputStream = new FileInputStream(req.getServletContext().getRealPath("/wsdl/TemperatureService.wsdl"));
byte[] buffer = new byte[1024];
resp.setContentType("application/xml");
int bytesRead = 0;
while ((bytesRead = wsdlInputStream.read(buffer)) != -1) {
resp.getOutputStream().write(buffer, 0, bytesRead);
}
wsdlInputStream.close();
resp.getOutputStream().flush();
}
}
}