如何显示在用户firebase中登录的电流

Question

    mAuth = FirebaseAuth.getInstance();
    mFirebaseDatabase = FirebaseDatabase.getInstance();
    myRef = mFirebaseDatabase.getReference().child("Users");
    FirebaseUser user = mAuth.getCurrentUser();
    userID = user.getUid();
    mAuthListener = new FirebaseAuth.AuthStateListener() {
        @Override
        public void onAuthStateChanged(@NonNull FirebaseAuth firebaseAuth) {
            FirebaseUser user = firebaseAuth.getCurrentUser();
            if (user != null) {
                // User is signed in
                Log.d(TAG, "onAuthStateChanged:signed_in:" + user.getUid());
            } else {
                // User is signed out
                Log.d(TAG, "onAuthStateChanged:signed_out");
                toastMessage("Successfully signed out.");
            }
            // ...
        }
    };
    myRef.addValueEventListener(new ValueEventListener() {
        @Override
        public void onDataChange(DataSnapshot dataSnapshot) {
            // This method is called once with the initial value and again
            // whenever data at this location is updated.
            showData(dataSnapshot);
        }
        @Override
        public void onCancelled(DatabaseError databaseError) {
        }
    });
}
/*private void showData(DataSnapshot dataSnapshot) {
    for(DataSnapshot ds : dataSnapshot.getChildren()){
        UserInformation uInfo = new UserInformation();
        uInfo.setName(ds.child(userID).getValue(UserInformation.class).getName()); //set the name
        uInfo.setHandicap(ds.child(userID).getValue(UserInformation.class).getHandicap()); //set the name
        uInfo.setAge(ds.child(userID).getValue(UserInformation.class).getAge()); //set the email
        uInfo.setGender(ds.child(userID).getValue(UserInformation.class).getGender()); //set the phone_num
        //display all the information
        Log.d(TAG, "showData: name: " + uInfo.getName());
        Log.d(TAG, "showData: age: " + uInfo.getAge());
        Log.d(TAG, "showData: handicap: " + uInfo.getHandicap());
        Log.d(TAG, "showData: gender: " + uInfo.getGender());
        ArrayList<String> array  = new ArrayList<>();
        array.add("Full Name:");
        array.add(uInfo.getName());
        array.add("Age:");
        array.add(uInfo.getAge());
        array.add("Handicap:");
        array.add(uInfo.getHandicap());
        array.add("Gender:");
        array.add(uInfo.getGender());
        ArrayAdapter adapter = new ArrayAdapter(this,android.R.layout.simple_list_item_1,array);
        mListView.setAdapter(adapter);
    }
}
*/
private void showData(DataSnapshot dataSnapshot) {
    ArrayList<String> array  = new ArrayList<>();
    for(DataSnapshot ds : dataSnapshot.getChildren()){
        UserInformation uInfo = ds.getValue(UserInformation.class);
        array.add(" Full Name /  " +uInfo.getName());
        array.add(" Age /  " + uInfo.getAge());
        array.add(" Handicap/ " + uInfo.getHandicap());
        array.add(" Gender/ " + uInfo.getGender());

    }
    ArrayAdapter adapter = new ArrayAdapter(this,android.R.layout.simple_list_item_1,array);
    mListView.setAdapter(adapter);
}
@Override
public void onStart() {
    super.onStart();
    mAuth.addAuthStateListener(mAuthListener);
}
@Override
public void onStop() {
    super.onStop();
    if (mAuthListener != null) {
        mAuth.removeAuthStateListener(mAuthListener);
    }
}
}
}

当前，每个用户差异化的方式是由UID登录时分配给它们的UID。当他们登录时，它们使用了存储在Firebase身份验证部分中的用户名和密码。验证用户后，他们将被直接进入其帐户页面。然后，在帐户页面上，我要求用户输入其个人详细信息，该详细信息保存在表用户下的实时数据库中。如何显示当前记录的用户信息？目前，它显示了用户表的详细信息，但我只希望它显示登录的用户的详细信息。输出显示在listView

Answer 1

首先获取登录的当前用户的UID：

FirebaseUser user = FirebaseAuth.getInstance().getCurrentUser();
String userid = user.getUid();

然后检索当前用户的数据：

DatabaseReference ref = FirebaseDatabase.getInstance().getReference("Users");
ref.child(userid).addListenerForSingleValueEvent(new ValueEventListener() {
@Override
public void onDataChange(DataSnapshot dataSnapshot) { 
String name = dataSnapshot.child("name").getValue().toString(); 
name1.setText(name);
}

假设您有这个：

Users
  userid
     name: peter
     //etc