如何用3个不断变化的值来循环这个语句，为40个文本字段设置文本

Question

这是我没有存储在列表中时的代码。这得到了我想在不同的文本字段中显示的内容，但我希望它更短，所以我想循环它

//"answerStoration.recovereDataChoices(i，TB("是来自其他类的函数，它返回一个数组列表；

quizAnswer1store.setText(answerStoration.retrieveDataChoices(1,TB).get(0));
quizAnswer2store.setText(answerStoration.retrieveDataChoices(1,TB).get(1));
quizAnswer3store.setText(answerStoration.retrieveDataChoices(1,TB).get(2));
quizAnswer4store.setText(answerStoration.retrieveDataChoices(1,TB).get(3));
quizAnswer1store2.setText(answerStoration.retrieveDataChoices(2,TB).get(0));
quizAnswer2store2.setText(answerStoration.retrieveDataChoices(2,TB).get(1));
quizAnswer3store2.setText(answerStoration.retrieveDataChoices(2,TB).get(2));
quizAnswer4store2.setText(answerStoration.retrieveDataChoices(2,TB).get(3));
quizAnswer1store3.setText(answerStoration.retrieveDataChoices(3,TB).get(0));
quizAnswer2store3.setText(answerStoration.retrieveDataChoices(3,TB).get(1));
quizAnswer3store3.setText(answerStoration.retrieveDataChoices(3,TB).get(2));
quizAnswer4store3.setText(answerStoration.retrieveDataChoices(3,TB).get(3));

我把它存储在一个列表"quizAnswerSTORE"中，我试图循环，但没有成功。

int k = 0;
for(int i = 0; i<quizAnswerSTORE.size(); i++){
for(int j = 1; j < 11; j++){
while(k<4){
quizAnswerSTORE.get(i).setText(answerStoration.retrieveDataChoices(j,TB).get(k));
}
}
}

预期的结果是在不同的40个txtfields中从数据库中diplay不同的值。因为每次循环值递增时，它都会以不同的值在我的数据库中滚动。J变量表示数据库中的id。K是由retrieveDataAnswers函数从四列数据库返回的arrayList中的值的索引。

给你。我希望你能解决这个问题。

Answer 1

您可以使用mod来控制最大int值，例如i % 10的值不能超过10。

示例：

public class Main {
public static void main(String[] args) {
int j = 1;
int k = 0;

for(int i = 0; i < 40; i++) {
System.out.println("quizAnswerSTORE"+i+".setText(answerStoration.retrieveDataChoices("+j+",TB).get("+k+"));");
k = (k + 1)%4;
if( k == 0) {
j = (j+1) % 11;
}
}
}
}

输出：

quizAnswerSTORE0.setText(answerStoration.retrieveDataChoices(1,TB).get(0));
quizAnswerSTORE1.setText(answerStoration.retrieveDataChoices(1,TB).get(1));
quizAnswerSTORE2.setText(answerStoration.retrieveDataChoices(1,TB).get(2));
quizAnswerSTORE3.setText(answerStoration.retrieveDataChoices(1,TB).get(3));
quizAnswerSTORE4.setText(answerStoration.retrieveDataChoices(2,TB).get(0));
quizAnswerSTORE5.setText(answerStoration.retrieveDataChoices(2,TB).get(1));
quizAnswerSTORE6.setText(answerStoration.retrieveDataChoices(2,TB).get(2));
quizAnswerSTORE7.setText(answerStoration.retrieveDataChoices(2,TB).get(3));
quizAnswerSTORE8.setText(answerStoration.retrieveDataChoices(3,TB).get(0));
quizAnswerSTORE9.setText(answerStoration.retrieveDataChoices(3,TB).get(1));
quizAnswerSTORE10.setText(answerStoration.retrieveDataChoices(3,TB).get(2));
quizAnswerSTORE11.setText(answerStoration.retrieveDataChoices(3,TB).get(3));
...
quizAnswerSTORE38.setText(answerStoration.retrieveDataChoices(10,TB).get(2));
quizAnswerSTORE39.setText(answerStoration.retrieveDataChoices(10,TB).get(3));

Answer 2

尽量与缩进保持一致，并将右括号"｝"与其对应的语句对齐。

我看到的这个代码的第一个问题是，k在while循环中永远不会递增，所以它将永远具有相同的值和循环。我看到的第二个问题是，k在while循环之后没有重置，所以当它第一次通过循环时(并且正确地递增(，它将保持在值4，并且在那之后每次都会跳过循环。

我不确定你想要实现什么(我可以使用更多的信息或样本输出(，但首先你可以通过将while循环更改为for循环来纠正循环错误

for (int i = 0; i < quizAnswerSTORE.size(); i++) {
for (int j = 1; j < 11; j++) {
for (int k = 0; k < 4; k++) {
quizAnswerSTORE.get(i).setText(answerStoration.retrieveDataChoices(j,TB).get(k));
}
}
}

或者，如果你想保持while循环，你可以这样做。

for (int i = 0; i < quizAnswerSTORE.size(); i++) {
for (int j = 1; j < 11; j++) {
int k = 0; // Set k inside the 2nd loop and it will reset to 0 after the while loop
while(k < 4) {
quizAnswerSTORE.get(i).setText(answerStoration.retrieveDataChoices(j,TB).get(k));
k++; // Shorthand for k += 1 which is shorthand for k = k + 1
}
}
}