我有以下sql:
WITH
ni AS (SELECT DISTINCT ON(issuercik) issuercik FROM new_insiders
WHERE date_filed > (CURRENT_DATE - INTERVAL '360 day')::date AND ( tickers @> '["MSFT"]'::jsonb ) ORDER BY issuercik, date_filed DESC),
t AS (SELECT cik FROM companies WHERE data->'tickers' @> '["MSFT"]'::jsonb )
SELECT ni.issuercik AS first, t.cik AS second FROM ni FULL OUTER JOIN t ON ni.issuercik = t.cik;
这给了我(正如预期的那样(:
789019 | 789019
现在,我需要参数化查询,但无法:
DEALLOCATE stmt;
PREPARE stmt AS WITH
ni AS (SELECT DISTINCT ON(issuercik) issuercik FROM new_insiders
WHERE date_filed > (CURRENT_DATE - INTERVAL '360 day')::date AND ( tickers @> '["$1"]'::jsonb ) ORDER BY issuercik, date_filed DESC),
t AS (SELECT cik FROM companies WHERE data->'tickers' @> '["$1"]'::jsonb )
SELECT ni.issuercik AS first, t.cik AS second FROM ni FULL OUTER JOIN t ON ni.issuercik = t.cik;
EXECUTE stmt('MSFT');
我得到一个空行,这是因为它实际上是在搜索"$1"
。我试图删除双引号,然后它抱怨
ERROR: invalid input syntax for type json
LINE 4: ...DATE - INTERVAL '360 day')::date AND ( tickers @> '[$1]'::js...
^
DETAIL: Token "$" is invalid.
我不知道如何解决这个问题。
如果只想检查数组是否包含给定值,可以使用?
而不是@>
。
这看起来像:
DEALLOCATE stmt;
PREPARE stmt AS
WITH
ni AS (
SELECT DISTINCT ON(issuercik) issuercik
FROM new_insiders
WHERE
date_filed > (CURRENT_DATE - INTERVAL '360 day')::date
AND tickers ? $1
ORDER BY issuercik, date_filed DESC
),
t AS (
SELECT cik
FROM companies
WHERE data->'tickers' ? $1
)
SELECT ni.issuercik AS first, t.cik AS second
FROM ni
FULL OUTER JOIN t ON ni.issuercik = t.cik;
EXECUTE stmt('MSFT');