打开字符串数组

Question

我有一个post操作的数组

$country = $_POST['country']; //The number of countries differ according to the user selection
$c = count($country);

输出:'

Array ( [0] => England,69,93 [1] => Australia,79,84 [2] => Greece,89,73 [3] => Germany,59,73 )`

我将不得不把它分解成一个多维数组，如:

> Array ( [0] => Array ( [0] => England [1] => 69 [2] => 93)
>         [1] => Array ( [0] => Australia [1] => 79 [2] => 84)                      
>         [2] => Array ( [0] => Greece [1] => 89 [2] => 73)
>         [3] => Array ( [0] => Germany [1] => 59 [2] => 73))

如何在PHP中实现

I tried

$r = array();
foreach($country as &$r){
  $r = explode(",", $r);
  //for($i = 0; $i < count($country); $i++){
    //for($j = 0; $j < count($r); $j++){
        //$array[$i][$j] = $r;
    //}
  //}
}
echo '<br>';
print_r($r);

for循环也不起作用，因此将其注释掉，但如果需要，将其作为一个选项。

print函数现在只打印数组的1。不太确定我做错了什么。任何帮助都是感激的。谢谢你

Answer 1

你就快到了:

$r = array();
foreach($country as $country_item){
  $r[] = explode(",", $country_item);
}
echo '<br>';
print_r($r);

以上应该可以运行。

如果你的国家在每个数组中都是唯一的，那对你来说可能更好:

$r = array();
foreach($country as $country_item){
  $temp_array = explode(",", $country_item);
  $r[$temp_array[0]] = array($temp_array[1], $temp_array[2]); 
}
echo '<br>';
print_r($r);

这会给你如下的输出:

> Array ( [England] => Array ( [0] => 69 [1] => 93)
>         [Australia] => Array ( [0] => 79 [1] => 84)                      
>         [Greece] => Array ( [0] => 89 [1] => 73)
>         [Germany] => Array ( [0] => 59 [1] => 73))

因此，这意味着您可以访问如下国家/地区的数据:

$r[$country_name];

Answer 2

try this

for($i=0;$i<count($country);$i++)
 {
      $country1[$i] = explode(",", $country[$i]);
 }

Answer 3

您正在用循环中的$r重写您的$r主数组-这是解决方案-始终除以变量:

$output = array();
foreach($country as $c){
  $parts = explode(',',$c);
  $output[] = $parts; 
}
print_r($output);