我有一个非常基本的应用程序,其中用户受到欢迎,并可以选择选择 1 或 2 并发送到回调脚本。每当我通过第一个菜单时,它都会给我一条"应用程序遇到错误"消息。
我的脚本如下:
<?php
// make an associative array of callers we know, indexed by phone number
$people = array(
"+15559990000"=>"A" );
// if the caller is known, then greet them by name
// otherwise, consider them just another caller
if(!$name = $people[$_REQUEST['From']])
$name = "caller";
// now greet the caller
header("content-type: text/xml");
echo "<?xml version="1.0" encoding="UTF-8"?>n";
?>
<Response>
<Gather action="process.php" numDigits="1">
<Say>Hello <?php echo $name ?>. Welcome to Choons by Yo-say.</Say>
<Say>To continue as <?php echo $name ?>, press 1.</Say>
<Say>If you are using a different number but would like to access your account, press 2</Say>
</Gather>
<!-- If customer doesn't input anything, prompt and try again. -->
<Say>Sorry, I didn't get your response.</Say>
</Response>
因此,该过程.php脚本如下所示:
<?php
header('Content-type: text/xml');
echo '<?xml version="1.0" encoding="UTF-8"?>';
echo '<Response>';
# @start snippet
$user_pushed = (int) $_REQUEST['Digits'];
# @end snippet
if ($user_pushed == 1)
{
echo '<Say>You pressed 1</Say>';
}
if ($user_pushed == 2)
{
echo '<Say>You pressed 2</Say>';
}
else {
// We'll implement the rest of the functionality in the
// following sections.
echo "<Say>Sorry, I can't do that yet.</Say>";
echo '<Redirect>mine-or-not.php</Redirect>';
}
echo '</Response>';
?>
当我拨入我的模拟账户时,它成功地完成了整个第一个脚本。但是在按"1"或"2"时,它只是说"抱歉,应用程序遇到错误"。谁能发现我的错误?
Twilio布道者。
有许多调试技巧:
检查应用程序监视器,了解 Twilio 在尝试向您的网站发出请求时捕获的内容。 通常,这会为您提供足够的信息来弄清楚发生了什么。 App Monitor 还允许您"重播"发送与原始请求相同的参数的单个 Webhook 请求,以帮助您诊断故障。
尝试在浏览器中加载PHP文件,或使用Fiddler或Postman等工具来模拟Twilio请求的HTTP请求。 这将允许您练习代码,像 Twilio 一样向他们发出 HTTP 请求,但您可以看到您的应用程序发送的响应。
希望有帮助。