我正在重新编码我已经创建的Web服务,以便我可以为我的小组其他成员使用Git创建一个"操作方法",他们将接管项目。
这次,我在尝试使用我的Web服务时开始遇到错误,我似乎找不到问题,因为代码看起来完全像我以前编码的(有效的代码)。
我正在使用apache tomcat和jersey和json。
这是错误:
mai 14, 2015 6:08:02 PM org.apache.catalina.core.StandardWrapperValve invoke
SEVERE: Allocate exception for servlet Jersey REST Service
com.sun.jersey.api.container.ContainerException: The ResourceConfig instance does not contain any root resource classes.
at com.sun.jersey.server.impl.application.RootResourceUriRules.<init>(RootResourceUriRules.java:99)
at com.sun.jersey.server.impl.application.WebApplicationImpl._initiate(WebApplicationImpl.java:1359)
at com.sun.jersey.server.impl.application.WebApplicationImpl.access$700(WebApplicationImpl.java:180)
at com.sun.jersey.server.impl.application.WebApplicationImpl$13.f(WebApplicationImpl.java:799)
at com.sun.jersey.server.impl.application.WebApplicationImpl$13.f(WebApplicationImpl.java:795)
at com.sun.jersey.spi.inject.Errors.processWithErrors(Errors.java:193)
at com.sun.jersey.server.impl.application.WebApplicationImpl.initiate(WebApplicationImpl.java:795)
at com.sun.jersey.server.impl.application.WebApplicationImpl.initiate(WebApplicationImpl.java:790)
at com.sun.jersey.spi.container.servlet.ServletContainer.initiate(ServletContainer.java:509)
at com.sun.jersey.spi.container.servlet.ServletContainer$InternalWebComponent.initiate(ServletContainer.java:339)
at com.sun.jersey.spi.container.servlet.WebComponent.load(WebComponent.java:605)
at com.sun.jersey.spi.container.servlet.WebComponent.init(WebComponent.java:207)
at com.sun.jersey.spi.container.servlet.ServletContainer.init(ServletContainer.java:394)
at com.sun.jersey.spi.container.servlet.ServletContainer.init(ServletContainer.java:577)
at javax.servlet.GenericServlet.init(GenericServlet.java:212)
at org.apache.catalina.core.StandardWrapper.loadServlet(StandardWrapper.java:1213)
at org.apache.catalina.core.StandardWrapper.allocate(StandardWrapper.java:827)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:129)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:103)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:293)
at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:861)
at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:606)
at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489)
at java.lang.Thread.run(Unknown Source)
这是我的web.xml文件:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>com.labtabdb.rest</display-name>
<welcome-file-list>
<welcome-file>readme.html</welcome-file>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>Jersey REST Service</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>com.labtabdb.rest</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Jersey REST Service</servlet-name>
<url-pattern>/nxp/*</url-pattern>
</servlet-mapping>
</web-app>
这是使用@path注释的类:
//url path for class it's methods/chemin url pour la classe et ses methodes
@Path ("/v1/inventory")
public class V1__inventory
{
@GET //url ending in only /v1/inventory /chemin terminé par /v1/inventory
@Produces(MediaType.APPLICATION_JSON)
public Response errorIfNoQueryParamSpecified() throws Exception
{
return Response
.status(400) //bad request
.entity("Error: Please specify extension and parameter for this search.")
.build();
}
/**
* Method that returns materials filter by material name
* @param material name
* @return Response
* @throws Exception
*/
@Path("/{material_label}")
@GET
@Produces(MediaType.APPLICATION_JSON)
public Response returnMaterial(@PathParam("material_label") String material) throws Exception
{
material = URLDecoder.decode(material, "UTF-8"); //decode URL param
String returnString = null;
JSONArray json;
try
{
json = LabTab_MySQLQuerys
.getMaterialsByName(material);
//if there are no results to the query
if(json.length() == 0)
throw new CustomException("No results returned");
else //otherwise return results
returnString = json.toString();
}
catch(CustomException e)
{
return Response
.status(204)
.entity(e.getMessage())
.build();
}
catch (Exception e)
{
e.printStackTrace();
return Response
.status(500) //internal server error
.entity("Server was not able to process your request")
.build();
}
return Response
.ok(returnString)
.build();
}
我已经一遍又一遍地搜索和阅读相同的文章已有3天了,但我还没有找到解决错误的解决方案。
所有帮助都得到赞赏
我要继续回答我自己的问题,希望它可以帮助一个新手休息。
我在创建教程时犯了一个非常愚蠢的错误:我的Web服务的" URL"是例如com.webservice.rest。重新完成项目时,我决定将包装的名称更改为与新URL相对应:因此,我的课程具有路径注释的班级,可以说,@path("/v1/cobtitory")将其更改为com。WebService.Inventory。
键入新的软件包名称时,我急于忘记在com.webservice中包含 rest 的单词。 rest .inventory。
编程Web服务时,您必须记住要确保每个包含路径注释的软件包的前缀是Web服务的URL。
确保所有范围内包含org.javassist:*
,因为泽西岛使用它来执行字节码操作和阴影jar的javassist
软件包不包括javassist
软件包。
<dependency>
<groupId>org.javassist</groupId>
<artifactId>javassist</artifactId>
<version>3.26.0-GA</version>
</dependency>