我正在写一个基本的链表程序。为了测试它,我只是创建了一个基本的列表,添加了一堆东西,然后试图删除它们。它抛出了一个错误,我不明白。
程序:
public static void main(String[] args) {
OrderedLinkedList one = new OrderedLinkedList();
for(int i = 0; i<=20; i=i+2){
one.add(i);
}
one.remove(3);
//System.out.println(one.toString());
}
我想看看如果我试图移除一个不存在的对象会发生什么。但是当我这样做的时候,它抛出了这个异常:
Exception in thread "main" java.lang.ClassCastException: java.lang.Integer cannot be cast to java.lang.String
异常似乎发生在包含compareTo()
方法的行中的我的remove方法中。我如何尝试将整型转换为字符串?当它传递给方法时,3不应该是一个可比性吗?
public boolean add(Comparable obj)
{
if(head.next == null){
OrderedListNode newNode = new OrderedListNode(obj, head, tail);
}
else{
OrderedListNode newNode = new OrderedListNode(obj,tail.previous,tail);
tail.previous.next = newNode;
tail.previous = newNode;
}
return true;
}
public boolean remove(Comparable obj)
{
OrderedListNode temp = head;
while(temp != null){
if(temp.theItem.compareTo(obj) == 0){
temp.previous.next = temp.next;
temp.next.previous = temp.previous;
}
else{
temp = temp.next;
}
}
return true;
}
/**
* Empty this OrderedLinkedList.
*/
public void clear()
{
// reset header node
head = new OrderedListNode("HEAD", null, null);
// reset tail node
tail = new OrderedListNode("TAIL", head, null);
// header references tail in an empty LinkedList
head.next = tail;
// reset size to 0
theSize = 0;
}
private class OrderedListNode{
Comparable theItem;
OrderedListNode next;
OrderedListNode previous;
public OrderedListNode(Comparable theItem, OrderedListNode previous, OrderedListNode next){
this.theItem = theItem;
this.next = next;
this.previous=previous;
}
}
@Override
public String toString()
{
String s = "";
OrderedListNode currentNode = head.next;
while (currentNode != tail)
{
s += currentNode.theItem.toString();
if (currentNode.next != tail)
{
s += ", ";
}
currentNode = currentNode.next;
}
return s;
}
您的问题在于清洁方法。它正在实例化字符串数据类型节点,并将其放入尾部和头部。所以当remove()被调用时,当它在你的对象列表中迭代/循环时,当它到达你的字符串类型节点时,异常被抛出,因为它试图比较int和string。
无论如何,我已经修复了你的问题通过重写部分代码。它不是完美的,但至少它不再触及问题
变化如下。
第一个:在remove方法中-你需要一个break语句,否则代码会进入无限循环。
我已经重做了你的Clean方法,因为它包含一些逻辑错误。基本上,您将希望在清理期间将事物设置为null或0,而不是为它初始化新的尾部和头部对象。第三:从逻辑上讲,add逻辑也是不正确的。我也做了重做。
注意:由于时间限制,我没有真正测试我自己的更改,所以可能仍然存在错误,这不在这个问题的范围内。
如果你发现任何错误,请留言回复,我会找时间再检查一次的。
public class OrderedLinkedList {
OrderedListNode head = null;
OrderedListNode tail = null;
int theSize = 0;
public boolean add(Comparable obj)
{
if(head == null){
head = new OrderedListNode(obj, head, tail);
}
else{
OrderedListNode newNode = new OrderedListNode(obj, /*prev=*/tail, /*next=*/null);
if (tail == null)
head.next = newNode;
else {
tail.next = newNode;
// tail.previous = newNode; No need this line. Already set in constructor
}
tail = newNode;
}
return true;
}
public boolean remove(Comparable obj)
{
OrderedListNode temp = head;
boolean elemRemoved = false;
while(temp != null){
if(temp.theItem.compareTo(obj) == 0) {
// dereference this object for garbage collection
if (temp.previous != null)
// Not a head - Head will not have previous
temp.previous.next = temp.next;
temp.next.previous = temp.previous;
elemRemoved = true;
break;
}
else{
temp = temp.next;
}
}
return elemRemoved;
}
/**
* Empty this OrderedLinkedList.
*/
public void clear()
{
// reset header node
head = null;
// reset tail node
tail = null;
// header references tail in an empty LinkedList
//head.next = tail;
// reset size to 0
theSize = 0;
}
private class OrderedListNode{
Comparable theItem;
OrderedListNode next;
OrderedListNode previous;
public OrderedListNode(Comparable theItem, OrderedListNode previous, OrderedListNode next){
this.theItem = theItem;
this.next = next;
this.previous=previous;
}
}
@Override
public String toString()
{
String s = "";
OrderedListNode currentNode = head.next;
while (currentNode != tail)
{
s += currentNode.theItem.toString();
if (currentNode.next != tail)
{
s += ", ";
}
currentNode = currentNode.next;
}
return s;
}
}
public class main {
public static void main(String[] args) {
OrderedLinkedList one = new OrderedLinkedList();
one.clear();
for(int i = 0; i<=20; i=i+2){
one.add(i);
}
boolean removedOK = one.remove(3);
System.out.println("Attempt 1 : Something was removed => " + removedOK);
removedOK = one.remove(2);
System.out.println("Attempt 2: Something was removed => " + removedOK);
removedOK = one.remove(4);
System.out.println("Attempt 3: Something was removed => " + removedOK);
}
}