我在比较两个范围时遇到问题。为了简单起见,我将采用两个简单的范围M6:M10
和M6:M8
,我想知道第二个范围是否包括在第一个范围中,我想做的第一件事是写
Sub example()
Dim range1, range2, inte As range
Set range1 = range("M6:M10")
Set range2 = range("M6:M8")
Set intersec = Intersect(range1, range2)
If intersec = range2 Then
[if statement]
End If
End Sub
但是这个过程会返回以下错误:
PRB: Error 13 (Type Mismatch) & Error 3061 w/ SQL Queries
所以也许我不能用这种方法"相交"。。。关于如何测试范围的包含性,有什么提示吗?非常感谢!
这里有一种方法:
Sub ProperSubSet()
Dim range1 As Range, range2 As Range, inte As Range
Dim r As Range
Set range1 = Range("M6:M10")
Set range2 = Range("M6:M8")
For Each r In range2
If Intersect(r, range1) Is Nothing Then
MsgBox "range2 is not a proper subset of range1"
Exit Sub
End If
Next r
MsgBox "range2 is a proper subset of range1"
End Sub
首先,将range1和range2变量声明为范围。
然后,当您将intersec变量与range2变量进行比较时,请使用range方法的address属性来比较内容。
类似于:
Sub example()
Dim range1 As Range, range2 As Range, intersec As Range
Set range1 = Range("M6:M10")
Set range2 = Range("M11:M12")
Set intersec = Intersect(range1, range2)
If Not intersec Is Nothing Then
If intersec.Address = range2.Address Then
'[CODE GOES HERE]
End If
End If
End Sub
以下是您可以尝试的东西:
Sub Test()
Dim R1 As Range, R2 As Range, R3 As Range
Set R1 = Application.InputBox("Select first range", , , , , , , 8)
Set R2 = Application.InputBox("Select second range", , , , , , , 8)
Set R3 = Intersect(R1, R2)
If Not R3 Is Nothing Then
If R3.Address = R1.Address Then
MsgBox "First Range is subset of second"
ElseIf R3.Address = R2.Address Then
MsgBox "Second Range is subset of first"
Else
MsgBox "Neither range contained in the other"
End If
Else
MsgBox "Ranges are disjoint"
End If
End Sub
我使用它的方式如下:
If Application.Intersect(rng1, rng2) Is Nothing Then
'herecomesthecode
Else
'herecomesthecode
End if
根据你想要实现的目标,你可以删除其他内容或写"不是什么都没有"。
另一个附加变体:
Sub ProperSubSet2()
Dim range1 As Range, range2 As Range
Set range1 = [M6:M10]
Set range2 = [M6:M8]
Set rComp = Intersect(range2, range1)
If Not rComp Is Nothing Then
If rComp.Cells.Count = range2.Cells.Count Then
MsgBox "range2 is a proper subset of range1"
Else
MsgBox "range2 is not a proper subset of range1"
End If
Else
MsgBox "Both ranges aren't intersected at all!"
End If
End Sub
您可以将交集与范围进行比较,以确定一个范围是否包含在另一个范围中。一些代码显示。。。
Sub TestExample()
Dim Range1 As Range: Set Range1 = Range("M6:M10")
Dim Range2 As Range: Set Range2 = Range("M6:M8")
MsgBox Example(Range1, Range2)
End Sub
Function Example(Range1 As Range, Range2 As Range) As Integer
Dim Overlay As Range: Set Overlay = Application.Intersect(Range1, Range2)
If Not Overlay Is Nothing Then
If Overlay.Address = Range1.Address Then Example = Example + 1
If Overlay.Address = Range2.Address Then Example = Example + 2
End If
End Function
如果没有一个范围完全包含在另一个范围内,函数将返回0,如果第一个范围包含在第二个范围内则返回1,如果第二个区域包含在第一个区域内则返回2,如果两个范围相等则返回3
对于一个更强大的解决方案,该解决方案适用于具有多个区域的区域、彼此不同的工作表上的区域、具有大量单元格的区域(所以.CountLarge,而不是.Count),那么这将起作用:
Function RangeContainsRange(BigRange As Range, SmallRange As Range) As Boolean
If BigRange.Parent Is SmallRange.Parent Then
RangeContainsRange = Application.Union(BigRange, SmallRange).Cells.CountLarge = BigRange.Cells.CountLarge
Else
RangeContainsRange = False
End If
End Function