将Odoo网站路由从公众更新到用户时出现内部错误

Question

我试图限制所有博客访问仅经过身份验证的用户，因为默认情况下所有博客文章都是公开的，我使用以下类来覆盖博客路由(例如/blog/myblogs-2(：

class RestrictWebBLog(WebsiteBlog):
@http.route(auth='user')
def blogs(self):
return super(RestrictWebBLog, self).blogs()
@http.route(auth='user')
def blog_post(self):
return super(RestrictWebBLog, self).blog_post()
@http.route(auth='user')
def blog(self):
return super(RestrictWebBLog, self).blog()

它似乎有效，因为尝试访问任何博客时都需要登录，但是输入凭据后，会出现以下错误：

错误信息：

blog() got an unexpected keyword argument 'blog'

Traceback (most recent call last):
File "/opt/odoo/odoo/addons/base/models/ir_http.py", line 203, in _dispatch
result = request.dispatch()
File "/opt/odoo/odoo/http.py", line 833, in dispatch
r = self._call_function(**self.params)
File "/opt/odoo/odoo/http.py", line 344, in _call_function
return checked_call(self.db, *args, **kwargs)
File "/opt/odoo/odoo/service/model.py", line 97, in wrapper
return f(dbname, *args, **kwargs)
File "/opt/odoo/odoo/http.py", line 337, in checked_call
result = self.endpoint(*a, **kw)
File "/opt/odoo/odoo/http.py", line 939, in __call__
return self.method(*args, **kw)
File "/opt/odoo/odoo/http.py", line 517, in response_wrap
response = f(*args, **kw)
TypeError: blog() got an unexpected keyword argument 'blog'

Answer 1

我认为您必须在与原始函数相同的函数中编写参数。

比如函数blogs()，在原来的函数中有更多的参数，比如

def blogs(self, page=1, **post):

因此，尝试像在原始函数中一样使用所有参数进行定义。