我试图重写过滤器,写在 Django 1.1 到 2.1 上
我有一个复杂的模型,称为Apartment
,其中包括一个Location
模型。Location
包括District
模型。
所以,我的模型代码:
class District(models.Model):
district_number = models.IntegerField(_('district'))
title = models.CharField(_('district name'), max_length=100)
city = models.ForeignKey(City, on_delete=models.PROTECT)
class Meta:
unique_together = ('city', 'district_number',)
def __str__(self):
return self.title
class Location(models.Model):
apartment = models.OneToOneField(Apartment, related_name='location', on_delete=models.CASCADE)
coordinate_long = models.DecimalField(max_digits=15, decimal_places=10)
coordinate_lat = models.DecimalField(max_digits=15, decimal_places=10)
zip_code = models.IntegerField(_('zip'))
district = models.ForeignKey(District, on_delete=models.PROTECT)
subway_station = models.ForeignKey(SubwayStation, on_delete=models.PROTECT)
city = models.ForeignKey(City, on_delete=models.PROTECT)
address = models.CharField(_('human readable address of apartment'), max_length=250)
def __str__(self):
return self.address
过滤器是
district = django_filters.ModelMultipleChoiceFilter(
name="location_district",
queryset=District.objects.all(),
)
在新版本中,我将name
更改为to_field_name
.
当我尝试启动时,这掉了一个错误 -Cannot resolve keyword 'district' into field. Choices are: apartment_type, apartment_type_id, bedrooms_count, co_ownership, date_added, descriptions, economy_effective, economy_effective_id, energy_effective, energy_effective_id, favorite_lists, financial_info, floor, id, is_published, location, manager, manager_id, photos, plan, price, publish_type, publish_type_id, rooms, rooms_count, services, square, title, video_url
我真的不明白ModelMultipleChoiceFilter
是如何工作的,以及如何从Location
上获取嵌套模型District
。
将ModelMultipleChoiceFilter
name
更改为field_name
,这对我来说效果很好。
通过查看文档,您可以看到to_name_field
将被映射到模型中的 Django 字段,因此您会收到 Django 无法"解析字段location_district
"的错误,因为您的模型中没有location_district
。 尽管从未使用过 DjangoFilters,但我相信如果您真的需要命名该字段,您可以将其指向location
。这意味着您的过滤器需要以下内容:
district = django_filters.ModelMultipleChoiceFilter(
name="location",
queryset=District.objects.all(),
)
或者你可以试试这个,但要注意我不知道它是否会起作用
district = django_filters.ModelMultipleChoiceFilter(
name="location__district",
queryset=District.objects.all(),
)