构建一个套接字程序，客户端发送2个向量，并且服务器执行点产品，并将结果作为响应发送给客户端

Question

我必须构建一个服务器 - 客户端程序，客户端发送2个向量（任何大小）和服务器执行点产品操作并将结果作为对客户端的响应发送。

示例：

Client:
V1= [5, 3,-1]
V2= [1, 2, 3]
Server:
Calculate the dot product as (1*5+2*3+3*-1) =8
Sends 8 to the client

这是处理客户端请求的服务器类 -

import java.io.IOException;
import java.io.PrintStream;
import java.net.ServerSocket;
import java.net.Socket;
import java.util.Scanner;
 /**
 *
 * @author Ehab Safaa
 */
public class server {
public static void main (String args []) throws IOException{
    int a[] = null;
    int b[] = null;
    int temp1;
    int temp2;
    int n = a.length;
    ServerSocket s1 = new ServerSocket (1342);
    Socket ss =s1.accept();
Scanner sc1= new Scanner(ss.getInputStream());
   for (int i = 0; i < a.length; i++) {
     a[i]=sc1.nextInt();}
     Scanner sc2= new Scanner(ss.getInputStream());
     for(int i=0 ;i < b.length; i++)
         b[i]=sc2.nextInt();
   int sum = 0;
    for (int i = 0; i < a.length; i++) {
        sum += a[n] * b[n];    
    }
PrintStream p =new PrintStream(ss.getOutputStream()); 
       }
}

这是向服务器发送请求的客户端类 -

 import java.io.IOException;
 import java.io.PrintStream;
 import java.net.Socket;
 import java.util.Scanner;
  /**
   *
   * @author Ehab Safaa
   */
    public class client {
     public static void main (String args [] ) throws IOException{
    int a[] = null ;
    int b[] = null;
    int temp1 ;
    int temp2;
    int n = a.length;
    Scanner sc =new Scanner(System.in);
    Socket s =new Socket("127.0.0.1",1342);
    Scanner sc1= new Scanner(System.in);
    System.out.println("enter the first array");
     for (int i = 0; i < a.length; i++) {
     a[i]=sc1.nextInt();}
    Scanner sc2= new Scanner(System.in);
    System.out.println("enter the second  array");
      for (int i = 0; i < b.length; i++) {
      b[i]=sc1.nextInt();
    }
      PrintStream p = new PrintStream(s.getOutputStream());
      p.println(a);
       PrintStream p1 = new PrintStream(s.getOutputStream());
     p1.println(b);
     temp1=sc1.nextInt();
      System.out.println(temp1);
    temp2=sc2.nextInt();
    System.out.println(temp2);
       }
    }     

任何帮助将不胜感激。

Answer 1

• 您想允许任何大小的向量 ，您使用客户端中的数组无法正常工作，因为a.length在输入数组之前无法反映长度。您可以改用ArrayList。当然，需要读取数量以外的元素的停止条件；您可以在输入行中使用findInLine()和一个零宽的阳性lookahead寻找另一个整数。
• 您可以通过提前发送向量长度来允许服务器使用数组。

import java.io.IOException;
import java.io.PrintStream;
import java.net.ServerSocket;
import java.net.Socket;
import java.util.Scanner;
public class server
{
    public static void main (String args []) throws IOException
    {
        ServerSocket s1 = new ServerSocket(1342);
        Socket ss = s1.accept();
        Scanner sc = new Scanner(ss.getInputStream()).useDelimiter("[\[,\s\]]+");
        int n = sc.nextInt();   // get length sent from client
        int a[] = new int[n];
        int b[] = new int[n];
        for (int i = 0; i < a.length; i++) a[i] = sc.nextInt();
        for (int i = 0; i < b.length; i++) b[i] = sc.nextInt();
        int sum = 0;
        for (int i = 0; i < a.length; i++) sum += a[i] * b[i];    
        PrintStream p = new PrintStream(ss.getOutputStream()); 
        p.print(sum);
    }
}

import java.io.IOException;
import java.io.PrintStream;
import java.net.Socket;
import java.util.Scanner;
import java.util.ArrayList;
public class client
{
    public static void main (String args [] ) throws IOException
    {
        ArrayList<Integer> a = new ArrayList<Integer>();
        ArrayList<Integer> b = new ArrayList<Integer>();
        Scanner sc = new Scanner(System.in);
        Socket s = new Socket("127.0.0.1", 1342);
        System.out.println("enter the first array");
        while (sc.findInLine("(?=[-+\d])") != null) a.add(sc.nextInt());
        sc.nextLine();
        System.out.println("enter the second array");
        while (sc.findInLine("(?=[-+\d])") != null) b.add(sc.nextInt());
        PrintStream p = new PrintStream(s.getOutputStream());
        p.println(a.size());    // make it easier for the server
        p.println(a);
        p.println(b);
        System.out.println((new Scanner(s.getInputStream())).nextInt());
    }
}