如何重定向到Admin登录页面，而不是Laravel 5.8.15中未经身份验证的管理员的登录页面

Question

有人知道如何在laravel 5.8.15(或简单的5.8(中的 redirectTo()方法中使用守卫？

我得到此错误

" app http middleware authenticate :: redirectto的声明($ request，$ guards(应与Illuminate airth airdware midderware authenticate authenticate euthenticate :: redirectto($ request(兼容

use IlluminateSupportFacadesRoute;
protected function redirectTo($request, $guards)
{
    if (! $request->expectsJson()) {
        if (array_first($this->guards) === 'admin') {
            return route('admin.login');
        }
        return route('login');
    }
}
//Updated code but still getting error
//Error:: Declaration of AppHttpMiddlewareAuthenticate::handle($request, 
  Closure $next, $guard = NULL) should be compatible with 
  IlluminateAuthMiddlewareAuthenticate::handle($request, Closure $next, 
  ...$guards)
//Code
....
use Closure;
use IlluminateSupportFacadesAuth;
.... 
public function handle($request, Closure $next, $guard = null)
{
    switch ($guard) {
        case 'admin':
            if (Auth::guard($guard)->check()) {
                return redirect()->route('admin.login');
            }
            break;
        default:
            if (Auth::guard($guard)->check()) {
                return redirect('/login');
            }
            break;
    }
    return $next($request);
}

Answer 1

这样检查，并重定向您的状况

    public function handle($request, Closure $next)
    {
        switch ($this->getGuard()) {
            case 'admin':
                if (!Auth::guard($guard)->check()) {
                    return redirect()->route('admin_login');
                }
                break;
            case 'vendor':
                if (!Auth::guard($guard)->check()) {
                    return redirect()->route('vendor_login');
                }
                break;
            case 'user':
                if (Auth::guard($guard)->check()) {
                    return redirect()->route('user_login');
                }
                break;
            default:
                if (Auth::guard($guard)->check()) {
                    return redirect('/login');
                }
                break;
        }

        return $next($request);
    }

Answer 2

修改App/Exceptions/Handler.php中的render($request, Exception $exception)看起来像下面的一个：

/**
 * Render an exception into an HTTP response.
 *
 * @param  IlluminateHttpRequest  $request
 * @param  Exception  $exception
 * @return IlluminateHttpResponse
 */
public function render($request, Exception $exception)
{
    if(get_class($exception) != 'IlluminateAuthAuthenticationException'){
        return parent::render($request, $exception);
    }

    $guard = Arr::get($exception->guards(),0);
    switch ($guard){
        case 'admin':
            return redirect(route('admin.login'));
            break;
        default:
            return redirect(route('login'));
            break;
    }
}