我有一段代码,如果找不到资源,我想在其中引发异常
Menu menu = menuService.findById(addMenuAmount.getMenuId())
.orElseThrow(com.tdk.web.exception.ResourceNotFoundException(“menu " +
addMenuAmount.getMenuId() + " not found "));
但是我得到了一个编译错误:
com.tdk.web.exception cannot be resolved to a type
尝试并确保com.tdk.web.exception.ResourceNotFoundException
是可访问的
Menu menu = menuService.findById(addMenuAmount.getMenuId())
.orElseThrow(() -> new com.tdk.web.exception.ResourceNotFoundException("menu " +
addMenuAmount.getMenuId() + " not found "));
注意lambda() ->
和引号"menu "
。