将字符串转换为电话号码 Ruby

Question

我用Ruby。我想将字符串转换为格式化电话号码。

例：

• 如果字符串有 10 个字符：

"0123456789"应转换为"0123-45-6789"

• 如果字符串有 11 个字符：

"01234567899"应转换为"0123-456-7899"

Answer 1

纯 Ruby 方式，请尝试String#insert

> "0123456789".insert(4, '-').insert(-5, '-')
#=> "0123-45-6789" 
> "01234567899".insert(4, '-').insert(-5, '-')
#=> "0123-456-7899" 

备注：负数表示您从字符串的

末尾计数，正数表示您从字符串的开头计数

Answer 2

如果你在Rails项目中工作，那么有一个内置的视图助手可以为你完成大部分的跑腿工作： http://api.rubyonrails.org/classes/ActionView/Helpers/NumberHelper.html#method-i-number_to_phone

number_to_phone[phone])                                     # => 555-1234
number_to_phone("5551234")                                   # => 555-1234
number_to_phone[phone])                                  # => 123-555-1234
number_to_phone[phone], area_code: true)                 # => [phone]
number_to_phone[phone], delimiter: " ")                  # => 123 555 1234
number_to_phone[phone], area_code: true, extension: 555) # => [phone] x 555
number_to_phone[phone], country_code: 1)                 # => [phone]
number_to_phone("123a456")                                   # => 123a456
number_to_phone("1234a567", raise: true)                     # => InvalidNumberError

因此，在您的情况下：

number_to_phone('0123456789') # => '0123-45-6789'
number_to_phone('01234567899') # => '0123-456-7899'

Answer 3

'0123456789'.gsub(/^(d{4})(d+)(d{4})$/, '1-2-3')
# => "0123-45-6789" 
'01234567899'.gsub(/^(d{4})(d+)(d{4})$/, '1-2-3')
# => "0123-456-7899" 

Answer 4

R = /(?<=A.{4})(.+)(?=.{4}z)/

def break_it(str)
  str.sub(R, '-1-')
end

break_it '0123456789'
  #=> "0123-45-6789" 
break_it '01234567899' 
  #=> "0123-456-7899" 

正则表达式可以细分如下。

(?<=      # begin a positive lookbehind
  A.{4}  # match four chars at the beginning of the string
)         # end positive lookbehind
(.+)      # match one or more chars and save to capture group 1
(?=       # begin a positive lookahead
  .{4}z  # match four chars at the end of the string 
)         # end positive lookahead
/