如何比较日期和得到最后日期，不应该是今天的日期

Question

我有一个数组的客户访问信息。数组的访问是升序的订单日期. .我要知道最后的探访记录但不应该是今天。

    stdClass Object
     (
        [0] => stdClass Object
                            (
                                [ID] => 39334
                                [ClassID] => 3193
                                [StartDateTime] => 2013-04-29T06:00:00
                                [LateCancelled] => 
                                [EndDateTime] => 2013-04-29T06:45:00
                           )
         [1] => stdClass Object
                            (
                                [ID] => 39334
                                [ClassID] => 3193
                                [StartDateTime] => 2013-04-30T06:00:00
                                [LateCancelled] => 
                                [EndDateTime] => 2013-04-30T06:45:00
                           )
     )

这里我想要得到第一个…可以有任意次数的访问。

Answer 1

$whatIneed = false;
foreach($myObj as $obj){
    // If this is today object just break, and object from previous loop is what you need
    if(date('dmY')==date('dmY',strtotime($obj->StartDateTime))) break;
    // saving object in loop into variable
    $whatIneed = $obj;
}
print_r($whatIneed);

Answer 2

您需要编写一个函数或方法来对对象数组进行排序。它必须接收一个对象数组作为参数，然后，例如，创建另一个数组，并一个接一个地添加对象，首先-最新的，从午夜开始，然后第二个…

Answer 3

foreach($obj as $valobj){
   // if curentdate is greater than db visit date then insert into array    
   if(strtotime(date('Y-m-d')) > strtotime(date('Y-m-d',$valobj->StartDateTime))){
            $arr[] = $valobj;
   }
}
print_r($arr);