设计 3(导轨 4)无法在没有密码的情况下更新用户

Question

我试图在不提供密码的情况下更新用户，但是在旧的设计/rails版本上工作的方法不再与设计3和rails 4强参数一起工作。

我正在使用我的user_controller来更新，但我也尝试使用自定义的设计注册控制器与device_parameter_sanitizer，没有成功。

表单不需要密码(没有密码字段)，处理更新的user_controller看起来像这样:

# PATCH/PUT /users/1
def update
  if user_params[:password].blank?
    Rails.logger.info "entered if statement"
    user_params.delete :password
    user_params.delete :password_confirmation
    Rails.logger.info(user_params.inspect)
  end
  @user = current_user
  if @user.update(user_params)
    redirect_to @user, notice: 'User was successfully updated.'
  else
    Rails.logger.info(@user.errors.inspect) 
    render action: 'edit'
  end
end
private
def user_params
  params.require(:user).permit(:screen_name, :full_name, :email, :about, 
    :location, :profile_pic, :password, :password_confirmation, :current_password)
end

. .提交后的日志如下:

Started PATCH "/users/13" for 127.0.0.1 at 2013-05-29 11:18:18 +0100
Processing by UsersController#update as HTML
Parameters: {"utf8"=>"✓", "authenticity_token"=>"20avah2OzaOVubAiam/SgvbYEQ4iijEWQqmNo7xD4rY=", "user"=>{"screen_name"=>"Darcbar", "full_name"=>"Barry Darcy", "about"=>"", "location"=>"", "website_url"=>"", "twitter_username"=>"", "email"=>"[e-mail]"}, "commit"=>"Save changes", "id"=>"13"}
User Load (0.5ms)  SELECT "users".* FROM "users" WHERE "users"."id" = 13 ORDER BY "users"."id" ASC LIMIT 1
Entered if statement...
{"screen_name"=>"Darcbar", "full_name"=>"Barry Darcy", "email"=>"[e-mail]", "about"=>"", "location"=>"", "twitter_username"=>"", "website_url"=>""}
(0.2ms)  BEGIN
User Exists (0.8ms)  SELECT 1 AS one FROM "users" WHERE ("users"."email" = '[e-mail]' AND "users"."id" != 13) LIMIT 1
(0.2ms)  ROLLBACK
#<ActiveModel::Errors:0x007fedf45bb640 @base=#<User id: 13, username: "darcbar", full_name: "Barry Darcy", about: "", location: "", email: "[e-mail]", encrypted_password: "$2a$10$Mb4zsRPPqZ9CYz0zdLMBU.62NyIk/T8s6Zw/uRTwWov3...", reset_password_token: nil, reset_password_sent_at: nil, remember_created_at: nil, sign_in_count: 9, current_sign_in_at: "2013-05-28 17:51:20", last_sign_in_at: "2013-05-28 16:42:52", current_sign_in_ip: "127.0.0.1", last_sign_in_ip: "127.0.0.1", authentication_token: nil, created_at: "2013-05-27 14:03:41", updated_at: "2013-05-28 17:51:20", screen_name: "Darcbar", profile_pic_file_name: nil, profile_pic_content_type: nil, profile_pic_file_size: nil, profile_pic_updated_at: nil>, 
  @messages={:password=>["please enter a password with at least 5 characters", "please enter a password with at least 5 characters"]}>
Rendered users/edit.html.haml within layouts/application (3.0ms)
Rendered partials/head/_user_options.haml (1.8ms)
Completed 200 OK in 74ms (Views: 12.1ms | ActiveRecord: 1.7ms)

有人知道为什么会出现密码错误吗?

Answer 1

密码验证来自用户模型:

validates :password, presence: true

解决方案是只在create时验证存在，在update时验证allow_blank:

validates :password, presence: true, length: {minimum: 5, maximum: 120}, on: :create
validates :password, length: {minimum: 5, maximum: 120}, on: :update, allow_blank: true

Answer 2

自2014年起，您可以简单地覆盖受保护的方法并执行:

class RegistrationsController < Devise::RegistrationsController
  protected
  def update_resource(resource, params)
    resource.update_without_password(params)
  end
end

Answer 3

您可以使用@user.update_without_password(user_params)方法来更新您的其他字段

例如，我在我的自定义users_controller.rb中有这个。我使用远程调用(ajax)进行更新。

#users_controller.rb
def update
  respond_to do |format|
    if needs_password?(@user, user_params)
      if @user.update_with_password(user_params_password_update)
        flash[:success] = 'User was successfully updated. Password was successfully updated'
        format.js {render 'update'}
      else
        error = true
      end
    else
      if @user.update_without_password(user_params)
        flash[:success] = 'User was successfully updated.'
        format.js {render 'update'}
      else
        error = true
      end
    end
    if error
      flash[:error] = @user.errors.full_messages.join(', ')
      format.js {render json: @user.errors.full_messages, status: :unprocessable_entity}
    end
  end
end
private
def needs_password?(user, user_params)
  !user_params[:password].blank?
end
def user_params
  params[:user].permit(:email, :password, :password_confirmation, :username, :full_name)
end
#Need :current_password for password update
def user_params_password_update
  params[:user].permit(:email, :password, :password_confirmation, :current_password, :username, :full_name)
end

Answer 4

密钥在此"user_params[:password].blank?"中。下面是代码示例:

def update
  if user_params[:password].blank?
    params = user_params_without_password
  else
    params = user_params
  end
  respond_to do |format|
    if @user.update(params)
      format.html { redirect_to @user, notice: t(:user_update) }
      format.json { render :show, status: :ok, location: @user }
    else
      format.html { render :edit }
      format.json { render json: @user.errors, status: :unprocessable_entity }
    end
  end
end
private
def set_user
  @user = User.find(params[:id])
end
# Never trust parameters from the scary internet, only allow the white list through.
def user_params
  params.require(:user).permit(:email, :username, :first_name, :last_name, :admin, :locked, :password)
end
def user_params_without_password
  params.require(:user).permit(:email, :username, :first_name, :last_name, :admin, :locked)
end

希望你能有所帮助

Answer 5

我在这个问题上徘徊了很长时间。答案都是可验证的，正如上面提到的mrstif。如果您使用validatable模块，则可以开箱使用(带有配置选项)，允许您在不提供密码的情况下更新用户详细信息，因此请非常小心滚动您自己的密码验证。

Answer 6

通过创建app/controller/registrations_controller来重写设计。rb

class RegistrationsController < Devise::RegistrationsController
  protected
  def update_resource(resource, params)
    resource.update(params.except(:current_password))
  end
end

此代码将直接更新用户参数，除了:current_password

devise_for :users, controllers: {registrations: 'registrations'}

Answer 7

我的目标是允许编辑用户属性而不需要密码，除非它是更改电子邮件，密码或删除帐户。以下是我的做法:

app/controllers/registrations_controller.rb:

class RegistrationsController < Devise::RegistrationsController
  before_action :configure_permitted_parameters
  ...
  def update
    params[:user][:team_attributes][:id] = current_user.team.id
    account_update_params = devise_parameter_sanitizer.sanitize(:account_update)
    if password_required?
      successfully_updated = resource.update_with_password(account_update_params)
    else
      account_update_params.delete(:current_password)
      successfully_updated = resource.update_without_password(account_update_params)
    end
    if successfully_updated
      sign_in resource, bypass: true
      redirect_to '/'
    else
      render :edit
    end
  end
  def destroy
    current_password = devise_parameter_sanitizer.sanitize(:account_update)[:current_password]
    resource.errors.add(:current_password, current_password.blank? ? :blank : :invalid)
    error_messages = 'Current password ' + resource.errors[:current_password].join
    if resource.destroy_with_password(current_password)
      redirect_to '/'
    else
      redirect_to delete_account_path, notice: error_messages
    end
  end
  protected
  def configure_permitted_parameters
        devise_parameter_sanitizer.permit(:account_update) do |user_params|
      user_params.permit(:username, :email, :password, :password_confirmation, :current_password, :name, :phone_number
    end
  end
  private
  def password_required?
    (resource.email != params[:user][:email] if params[:user][:email].present?) || params[:user][:password].present?
  end
end

更新配置/routes.rb:

devise_for :users, controllers: { registrations: 'registrations' }

在视图/设计/注册/edit.html.haml

# edit form
...
= simple_nested_form_for(resource, as: resource_name, url: registration_path(resource_name), html: { class: 'mo-form' }, defaults: { placeholder: false, hint: false }) do |f|
...
# delete form
...
= simple_form_for(resource, as: resource_name, url: user_registration_path(resource_name), method: :delete, html: { class: 'mo-form' }, defaults: { placeholder: false, hint: false }) do |f|
...

Answer 8

我在这种情况下使用了update_columns方法。例如，它避免了绕过密码验证。

@user.update_columns(user_params)

但是，此方法不会修改updated_at字段的时间戳，这也需要通过合并{ updated_at: Time.current }或touch来解决。