我正在尝试将一些JSON数据反序列化为应用程序的对象。到目前为止，它还可以，因为JSON数据上的属性是静态的(带值的键)。现在我得到了一个结果，其中键是一个动态数据块。
下面是一个JSON url示例:http://en.wikipedia.org/w/api.php?action=query&格式= json& pageids = 6695,支撑= info
结果JSON为:
{ "query" : { "pages" : { "6695" : { "counter" : "",
"lastrevid" : 468683764,
"length" : 8899,
"ns" : 0,
"pageid" : 6695,
"title" : "Citadel",
"touched" : "2012-01-03T19:16:16Z"
} } } }
好的，这很好，除了我不能反序列化"pages"数据到一个对象。如果我要为这些页面定义一个类，它应该是这样的:
public class 6695
{
public string counter { get; set; }
public int lastrevid { get; set; }
public int length { get; set; }
public int ns { get; set; }
public int pageid { get; set; }
public string title { get; set; }
public string touched { get; set; }
}
为了对内容进行反序列化(使用JsonConvert.Deserialize(jsondata))我们都知道我们不能有一个名为6695的类。不仅如此，类的名称也必须不同(例如pageid=7145必须是7145类)。
我似乎可以拔一些值，如果我使用类似JObject.Parse(内容)，然后访问项目作为jarray，但它是相当丑陋的，我仍然坚持试图从页面数组中取出数据。
找人帮忙。我不认为这是不寻常的，它只是不是JSON数据我以前遇到过，不知道如何处理它。
谢谢!
PS忘了说这是在Windows Phone 7上，所以"动态"是不可用的!
最简单的方法。在这种特殊情况下，可能是dynamic。
dynamic data = Newtonsoft.Json.JsonConvert.DeserializeObject<dynamic>(json);
var lastRevId = data.query.pages["6695"].lastrevid;
你可以通过它的[]名称引用任何元素，所以你可以做一些像data["query"]["pages"]["6695"]["lastrevid"]。这将绕过所有在c#中名字无效的小对象
如何使用https://github.com/facebook-csharp-sdk/simple-json (https://nuget.org/packages/SimpleJson)
var text = "{"query":{"pages":{"6695":{"pageid":6695,"ns":0,"title":"Citadel","touched":"2012-01-03T19:16:16Z","lastrevid":468683764,"counter":"","length":8899}}}}";
dynamic json = SimpleJson.DeserializeObject(text);
string title = json.query.pages["6695"].title;
foreach (KeyValuePair<string, dynamic> page in json.query.pages)
{
var id = page.Key;
var pageId = page.Value.pageid;
var ns = page.Value.ns;
}
(使用强类型类)
class result
{
public query query { get; set; }
}
class query
{
public IDictionary<string, page> pages { get; set; }
}
class page
{
public long pageid { get; set; }
public string title { get; set; }
}
var result = SimpleJson.DeserializeObject<result>(text);
在不支持动态的Windows phone上，并且你不想使用强类型的类。
var json = (IDictionary<string, object>)SimpleJson.DeserializeObject(text);
var query = (IDictionary<string, object>)json["query"];
var pages = (IDictionary<string, object>)query["pages"];
var pageKeys = pages.Keys;
var page = (IDictionary<string, object>)pages["6695"];
var title = (string)page["title"];
我希望下面的例子会有所帮助。我总是设计一个与json匹配的模型。当对象是您自己的模型设计时，使用它要好得多。
从json中生成c#模型是非常容易的。我使用这个网站来生成模型:http://json2csharp.com一个完整的例子是:
c#代码: var targetsObject = Newtonsoft.Json.JsonConvert.DeserializeObject<YourModel>(jsonString);
{
"investors": [
{
"name": "06",
"programs": [
{
"name": "Conventional",
"value": "3.5"
},
{
"name": "FHA - Standard",
"value": "5.0"
},
{
"name": "FHA - Streamline",
"value": ""
},
{
"name": "VA",
"value": "5.5"
},
{
"name": "VA IRRRL",
"value": "6.0"
},
{
"name": "Non-Prime",
"value": ""
}
]
},
{
"name": "07",
"programs": [
{
"name": "Conventional",
"value": "3.5"
},
{
"name": "FHA - Standard",
"value": "5.0"
},
{
"name": "FHA - Streamline",
"value": "7.0"
},
{
"name": "VA",
"value": "5.5"
},
{
"name": "VA IRRRL",
"value": ""
},
{
"name": "Non-Prime",
"value": ""
}
]
},
{
"name": "08",
"programs": [
{
"name": "Conventional",
"value": "3.5"
},
{
"name": "FHA - Standard",
"value": "5.0"
},
{
"name": "FHA - Streamline",
"value": "7.0"
},
{
"name": "VA",
"value": "5.5"
},
{
"name": "VA IRRRL",
"value": ""
},
{
"name": "Non-Prime",
"value": ""
}
]
},
{
"name": "09",
"programs": [
{
"name": "Conventional",
"value": "3.5"
},
{
"name": "FHA - Standard",
"value": "5.0"
},
{
"name": "FHA - Streamline",
"value": ""
},
{
"name": "VA",
"value": "5.5"
},
{
"name": "VA IRRRL",
"value": ""
},
{
"name": "Non-Prime",
"value": ""
}
]
},
{
"name": "10",
"programs": [
{
"name": "Conventional",
"value": ""
},
{
"name": "FHA - Standard",
"value": ""
},
{
"name": "FHA - Streamline",
"value": ""
},
{
"name": "VA",
"value": ""
},
{
"name": "VA IRRRL",
"value": ""
},
{
"name": "Non-Prime",
"value": "2.0"
}
]
},
{
"name": "11",
"programs": [
{
"name": "Conventional",
"value": "3.5"
},
{
"name": "FHA - Standard",
"value": "5.0"
},
{
"name": "FHA - Streamline",
"value": ""
},
{
"name": "VA",
"value": "6.0"
},
{
"name": "VA IRRRL",
"value": "6.0"
},
{
"name": "Non-Prime",
"value": ""
}
]
},
{
"name": "12",
"programs": [
{
"name": "Conventional",
"value": "3.5"
},
{
"name": "FHA - Standard",
"value": "5.0"
},
{
"name": "FHA - Streamline",
"value": ""
},
{
"name": "VA",
"value": "5.5"
},
{
"name": "VA IRRRL",
"value": "6.0"
},
{
"name": "Non-Prime",
"value": ""
}
]
},
{
"name": "13",
"programs": [
{
"name": "Conventional",
"value": ""
},
{
"name": "FHA - Standard",
"value": "5.0"
},
{
"name": "FHA - Streamline",
"value": ""
},
{
"name": "VA",
"value": ""
},
{
"name": "VA IRRRL",
"value": ""
},
{
"name": "Non-Prime",
"value": "2.0"
}
]
}
]
}
模型:
public class Program
{
public string name { get; set; }
public string value { get; set; }
}
public class Investor
{
public string name { get; set; }
public List<Program> programs { get; set; }
}
public class RootObject
{
public List<Investor> investors { get; set; }
}
使用Json.net可以这样做:
Dictionary<string,object> result = JsonConvert.DeserializeObject<Dictionary<string,object>>(json);
foreach(var item in result)
Console.WriteLine(item.Key + " " + item.Value);
如何在JSON字符串中进行简单的搜索和替换?虽然它可能不是最优雅的解决方案，但它可能是最实用的解决方案。
也许您可以只使用一个保留属性来包含对象类型，然后使用本文所示的基类型:带JSON的动态类型。净