在Gulp中插入后删除原始文件

Question

我想把我的文件合并到一个文件中，然后删除原始文件。我应该如何在默认任务中解决此问题？

var es = require('event-stream');
var concat = require('gulp-concat');
var unique = require('array-unique');
function concatGroup(groupName, group){
    return gulp.src(unique(group.files))
        .pipe(concat(groupName + '.js'))
        .pipe(gulp.dest(group.target));
}
gulp.task('default', function () {
    var groups = {
        test: {
            files: [array of files],
            target: "target dir"
        },
        test2: {
            files: [array of files],
            target: "target dir"
        },
        test3: {
            files: [array of files],
            target: "target dir"
        }
    };
    var streams = [];
    for (var groupName in groups) {
        streams.push(concatGroup(groupName, groups[groupName]));
    }
    return es.concat.apply(es, streams);
});

Answer 1

只需侦听流中的end事件，然后使用del:

var concat = require('gulp-concat');
var unique = require('array-unique');
var del = require('del');
gulp.task('default', function (done) {
  var groupName = "test",
      group = {
        files: [array of files],
        target: "target dir"
      };
  var files = unique(group.files)
  gulp.src(files)
    .pipe(concat(groupName + '.js'))
    .pipe(gulp.dest(group.target))
    .on('end', function() {
      del(files).then(function() {
        done();
      });
    });
});

Answer 2

感谢大家的帮助，这是我的最后一段代码，运行良好。我只需要创建一个新的空流，并将其返回给事件流合并，并在文件删除时标记为完成。

var es = require('event-stream');
var concat = require('gulp-concat');
var unique = require('array-unique');
var del = require('del');
function concatGroup(groupName, group) {
    var stream = through.obj();
    gulp.src(unique(group.files))
        .pipe(concat(groupName + '.js'))
        .pipe(gulp.dest(group.target))
        .on('end', function () {
            del(group.files).then(function () {
                stream.end();
            });
        });
    return stream;
}
gulp.task('default', function () {
    var groups = {
        test: {
            files: [array of files],
            target: "target dir"
        },
        test2: {
            files: [array of files],
            target: "target dir"
        },
        test3: {
            files: [array of files],
            target: "target dir"
        }
    };
    var streams = [];
    for (var groupName in groups) {
        streams.push(concatGroup(groupName, groups[groupName]));
    }
    return es.concat.apply(es, streams);
});