修复无效JSON的最有效方法

我陷入了一个不可能的境地。我有一个来自外太空的JSON（他们不可能改变它）。这是JSON

{
    user:'180111',
    title:'I'm sure "E pluribus unum" means 'Out of Many, One.' nnhttp://en.wikipedia.org/wiki/E_pluribus_unum.nn'',
    date:'2007/01/10 19:48:38',
    "id":"3322121",
    "previd":112211,
    "body":"'You' can "read" more here [url=http://en.wikipedia.org/?search=E_pluribus_unum]E pluribus unum[/url]'s. Cheers \*/ :/",
    "from":"112221",
    "username":"mikethunder",
    "creationdate":"2007/01/10 14:04:49"
}

"它根本不是一个有效的JSON"，我说。他们的回答是"emmm！但Javascript可以毫无怨言地阅读":

<html>
<script type="text/javascript">
    var obj = {"PUT JSON FROM UP THERE HERE"};
    document.write(obj.title);
    document.write("<br />");
    document.write(obj.creationdate + " " + obj.date);
    document.write("<br />");
    document.write(obj.body);
    document.write("<br />");
</script>
<body>
</body>
</html>

问题

我应该通过.NET（4）读取和解析这个字符串，它打破了Json.org C#部分提到的14个库中的3个（没有尝试其他库）。为了解决这个问题，我编写了以下函数来修复单引号和双引号的问题。

public static string JSONBeautify(string InStr){
    bool inSingleQuote = false;
    bool inDoubleQuote = false;
    bool escaped = false;
    StringBuilder sb = new StringBuilder(InStr);
    sb = sb.Replace("`", "<°)))><"); // replace all instances of "grave accent" to "fish" so we can use that mark later. 
                                        // Hopefully there is no "fish" in our JSON
    for (int i = 0; i < sb.Length; i++) {
        switch (sb[i]) {
            case '\':
                if (!escaped)
                    escaped = true;
                else 
                    escaped = false;
                break;
            case ''':
                if (!inSingleQuote && !inDoubleQuote) {
                    sb[i] = '"';            // Change opening single quote string markers to double qoute
                    inSingleQuote = true;
                } else if (inSingleQuote && !escaped) {
                    sb[i] = '"';            // Change closing single quote string markers to double qoute
                    inSingleQuote = false;
                } else if (escaped) {
                    escaped = false;
                }
                break;
            case '"':
                if (!inSingleQuote && !inDoubleQuote) {
                    inDoubleQuote = true;   // This is a opening double quote string marker
                } else if (inSingleQuote && !escaped) {
                    sb[i] = '`';            // Change unescaped double qoute to grave accent
                } else if (inDoubleQuote && !escaped) {
                    inDoubleQuote = false; // This is a closing double quote string marker
                } else if (escaped) {
                    escaped = false;
                }
                break;
            default:
                escaped = false;
                break;
        }
    }
    return sb.ToString()
        .Replace("\/", "/")        // Remove all instances of escaped / (/) .hopefully no smileys in string
        .Replace("`", "\"")       // Change all "grave accent"s to escaped double quote "
        .Replace("<°)))><", "`")   // change all fishes back to "grave accent"
        .Replace("\'","'");        // change all escaped single quotes to just single quote
}

现在JSONlint只抱怨属性名称，我可以使用JSON.NET和SimpleJSON库来解析上面的JSON。

问题

我确信我的代码不是修复上述JSON的最佳方法。是否存在我的代码可能被破坏的情况？有更好的方法吗？

您需要通过JavaScript运行它。在.net中启动一个JavaScript解析器。将字符串作为JavaScript的输入，并使用JavaScript的原生JSON.stringify进行转换：

obj = {
    "user":'180111',
    "title":'I'm sure "E pluribus unum" means 'Out of Many, One.' nnhttp://en.wikipedia.org/wiki/E_pluribus_unum.nn',
    "date":'2007/01/10 19:48:38',
    "id":"3322121",
    "previd":"112211",
    "body":"'You' can "read" more here [url=http://en.wikipedia.org/?search=E_pluribus_unum]E pluribus unum[/url]'s. Cheers \*/ :/",
    "from":"112221",
    "username":"mikethunder",
    "creationdate":"2007/01/10 14:04:49"
}
console.log(JSON.stringify(obj));
document.write(JSON.stringify(obj));

请记住，您得到的字符串（或者更确切地说是对象）不是有效的JSON，无法使用JSON库进行解析。它需要首先转换为有效的JSON。但是它是有效的JavaScript。

要完成此答案：您可以在.Net中使用JavaScriptSerializer。对于此解决方案，您需要以下程序集：

System.Net

System.Web.Script.Serialization

var webClient = new WebClient();
string readHtml = webClient.DownloadString("uri to your source (extraterrestrial)");
var a = new JavaScriptSerializer();
Dictionary<string, object> results = a.Deserialize<Dictionary<string, object>>(readHtml);

这个怎么样：

 string AlienJSON = "your alien JSON";
 JavaScriptSerializer js = new JavaScriptSerializer();
 string ProperJSON = js.Serialize(js.DeserializeObject(AlienJSON));

或者只是在反序列化后使用对象，而不是将其转换回字符串并将其传递给JSON解析器以获得额外的头痛

正如Mouser还提到的，您需要使用System.Web.Script.Serialization，这可以通过在项目中包含System.Web.extensions.dll来实现，为此，您需要将项目属性中的Target framework更改为.NET Framework 4。

编辑

使用反序列化对象的诀窍是使用dynamic

JavaScriptSerializer js = new JavaScriptSerializer();
dynamic obj = js.DeserializeObject(AlienJSON);

对于问题中的JSON，只需使用

string body = obj["body"];

或者如果您的JSON是数组

if (obj is Array) {
    foreach(dynamic o in obj){
        string body = obj[0]["body"];
        // ... do something with it
    }
}

这里有一个我制作的函数，它将修复损坏的json:

function fixJSON(json){
    function bulkRegex(str, callback){
        if(callback && typeof callback === 'function'){
            return callback(str);
        }else if(callback && Array.isArray(callback)){
            for(let i = 0; i < callback.length; i++){
                if(callback[i] && typeof callback[i] === 'function'){
                    str = callback[i](str);
                }else{break;}
            }
            return str;
        }
        return str;
    }
    if(json && json !== ''){
        if(typeof json !== 'string'){
            try{
                json = JSON.stringify(json);
            }catch(e){return false;}
        }
        if(typeof json === 'string'){
            json = bulkRegex(json, false, [
                str => str.replace(/[nt]/gm, ''),
                str => str.replace(/,}/gm, '}'),
                str => str.replace(/,]/gm, ']'),
                str => {
                    str = str.split(/(?=[,}]])/g);
                    str = str.map(s => {
                        if(s.includes(':') && s){
                            let strP = s.split(/:(.+)/, 2);
                            strP[0] = strP[0].trim();
                            if(strP[0]){
                                let firstP = strP[0].split(/([,{[])/g);
                                firstP[firstP.length-1] = bulkRegex(firstP[firstP.length-1], false, p => p.replace(/[^A-Za-z0-9-_]/, ''));
                                strP[0] = firstP.join('');
                            }
                            let part = strP[1].trim();
                            if((part.startsWith('"') && part.endsWith('"')) || (part.startsWith(''') && part.endsWith(''')) || (part.startsWith('`') && part.endsWith('`'))){
                                part = part.substr(1, part.length - 2);
                            }
                            part = bulkRegex(part, false, [
                                p => p.replace(/(["])/gm, '\$1'),
                                p => p.replace(/\'/gm, '''),
                                p => p.replace(/\`/gm, '`'),
                            ]);
                            strP[1] = ('"'+part+'"').trim();
                            s = strP.join(':');
                        }
                        return s;
                    });
                    return str.join('');
                },
                str => str.replace(/(['"])?([a-zA-Z0-9-_]+)(['"])?:/g, '"$2":'),
                str => {
                    str = str.split(/(?=[,}]])/g);
                    str = str.map(s => {
                        if(s.includes(':') && s){
                            let strP = s.split(/:(.+)/, 2);
                            strP[0] = strP[0].trim();
                            if(strP[1].includes('"') && strP[1].includes(':')){
                                let part = strP[1].trim();
                                if(part.startsWith('"') && part.endsWith('"')){
                                    part = part.substr(1, part.length - 2);
                                    part = bulkRegex(part, false, p => p.replace(/(?<!\)"/gm, ''));
                                }
                                strP[1] = ('"'+part+'"').trim();
                            }
                            s = strP.join(':');
                        }
                        return s;
                    });
                    return str.join('');
                },
            ]);
            try{
                json = JSON.parse(json);
            }catch(e){return false;}
        }
        return json;
    }
    return false;
}

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