Symfony2/将查询结果类型转换为simpeler对象



我正在使用Stof的DoctrineExtension捆绑包来检索我的树,现在我想将该树转换为数组(然后将其转换为json)。

NestedTreeDepository->childrenHierarchy()的格式不正确,但我想修改输出,以便只返回节点"title"属性和"id"属性,并将任何子级放在"children"子数组中。符合此格式(JSON):

{
        label: 'node1',
        children: [
            { label: 'child1' },
            { label: 'child2' }
        ]
    },
    {
        label: 'node2',
        children: [
            { label: 'child3' }
        ]
    }
}

我已经尝试过以下代码,它返回的结果与childrenHierarchy()相同,但允许我修改查询。

    $query = $em
            ->createQueryBuilder()
            ->select('node')
            ->from('MyBundle:Page', 'node')
            ->orderBy('node.root, node.lft', 'ASC')
            ->getQuery()
    ;
    $nodes = $query->getArrayResult();
    [Do magic here]
    $tree = $pagerepo->buildTree($nodes);

是否可以将每个节点类型转换为一个更简单的对象,该对象只包含以下属性:

  • id
  • 所有权
  • 用于定位的其他一些int

如果我通过json_encode()运行它,我就会得到我所需要的。

当然欢迎任何其他解决方案。

我为此编写的代码(几个小时前刚刚编写)它是stof的buildTreeArray函数的重制版

在控制器中(我为symfony2写这篇文章):

function gettreeAction {
    $query = .... // do your query
    $tree = $this->buildTree($query->getArrayResult());
    $response = new Response(json_encode($tree));
    return $response;
}
private function buildTree($nodes) 
{
    $nestedTree = array();
    $l = 0;
    if (count($nodes) > 0) {
        // Node Stack. Used to help building the hierarchy
        $stack = array();
        foreach ($nodes as $child) {
            $item = array();
            $item['name'] = $child['title'];
            $item['id'] = 'page_'.$child['id'];
            $item['level'] = $child['level'];
            $item['children'] = array();
            // Number of stack items
            $l = count($stack);
            // Check if we're dealing with different levels
            while($l > 0 && $stack[$l - 1]['level'] >= $item['level']) {
                array_pop($stack);
                $l--;
            }
            // Stack is empty (we are inspecting the root)
            if ($l == 0) {
                // Assigning the root child
                $i = count($nestedTree);
                $nestedTree[$i] = $item;
                $stack[] = &$nestedTree[$i];
            } else {
                // Add child to parent
                $i = count($stack[$l - 1]['children']);
                $stack[$l - 1]['children'][$i] = $item;
                $stack[] = &$stack[$l - 1]['children'][$i];
            }
        }
    }
    return $nestedTree;
}

与jqTree完美配合。。。

我已经解决了如下问题:

public function getPageTreeAction() {
    $pagerepo = $this->getDoctrine()->getRepository('MyBundle:Page');
    $em = $this->getDoctrine()->getEntityManager();
    $query = $em
            ->createQueryBuilder()
            ->select('node')
            ->from('MyCorpBundle:Page', 'node')
            ->orderBy('node.root, node.lft', 'ASC')
            ->getQuery();
    $flatnodearray = $query->getArrayResult();
    $flatsimplenodearray = array();
    foreach ($flatnodearray as $currentNode) {
        $currentSimpleNode = array();
        $currentSimpleNode['id'] = $currentNode['id'];
        $currentSimpleNode['lft'] =$currentNode['lft'];
        $currentSimpleNode['rgt'] = $currentNode['rgt'];
        $currentSimpleNode['lvl'] = $currentNode['lvl'];
        $currentSimpleNode['title'] = $currentNode['title'];
        $flatsimplenodearray[] = $currentSimpleNode;
    }
    $tree = $pagerepo->buildTree($flatsimplenodearray);
    $response = new Response(json_encode($tree));
    $response->headers->set('Content-Type', 'application/json');
    return $response;
}

我会使用Stofs Repository函数来获取分层数组中的节点:

$repo = $em->getRepository('MyBundle:Page');
$arrayTree = $repo->childrenHierarchy();

我认为除了手动修改数组之外,没有其他解决方案了。删除一些不需要的属性后,可以对数组进行json_encode并返回它。

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