如何使用 joda 时间排除日期范围内的周末



我正在尝试使用乔达时间查找工作日。但是在这里我遇到了一个问题,即四月没有给出正确的结果。我发布代码以及我从代码中获得的输出。

public class ExcludingWeekEnds {
public static List<LocalDate> dateList = new ArrayList<LocalDate>();
public static void main(String[] args) {
    final LocalDate start = new LocalDate(2015,4,1);
    final LocalDate end = new LocalDate(2015, 4, 30);

    LocalDate weekday = start;
    if (start.getDayOfWeek() == DateTimeConstants.SATURDAY ||
            start.getDayOfWeek() == DateTimeConstants.SUNDAY) {
        weekday = weekday.plusWeeks(1).withDayOfWeek(DateTimeConstants.MONDAY);
    }
    while (weekday.isBefore(end)) {
        System.out.println(weekday);
        dateList.add(weekday);
        if (weekday.getDayOfWeek() == DateTimeConstants.FRIDAY)
            weekday = weekday.plusDays(3);
        else
            weekday = weekday.plusDays(1);
    }
    System.out.println(dateList.size());
}
} 

这是我得到的输出

2015-04-01
2015-04-02
2015-04-03
2015-04-06
2015-04-07
2015-04-08
2015-04-09
2015-04-10
2015-04-13
2015-04-14
2015-04-15
2015-04-16
2015-04-17
2015-04-20
2015-04-21
2015-04-22
2015-04-23
2015-04-24
2015-04-27
2015-04-28
2015-04-29
21

有人帮助我

正如马文在评论中所说,你应该修改你的条件,同时:

while (!weekday.isAfter(end)) { // Modify HERE
    System.out.println(weekday);
    dateList.add(weekday);
    if (weekday.getDayOfWeek() == DateTimeConstants.FRIDAY)
        weekday = weekday.plusDays(3);
    else
        weekday = weekday.plusDays(1);
}

因此,您可以获得包括结束在内的结果。

最新更新