,它总是获得计数值
我已经在 odoo 10
中定义了computed field
,现在我想在 search orm
中获得其值,但它的值保持为false,当我尝试store=True
时,它的值不会更改。如果有人有解决方案,请告诉我,我非常感谢。我的代码是:
balance_amount = fields.Float(string="Balance Amount", compute='_compute_loan_amount')
@api.one
def _compute_loan_amount(self):
total_paid = 0.0
for loan in self:
for line in loan.loan_lines:
if line.paid:
total_paid += line.amount
balance_amount = loan.loan_amount - total_paid
self.total_amount = loan.loan_amount
self.balance_amount = balance_amount
self.total_paid_amount = total_paid
当我在下面使用search_count
时:
loan_count = self.env['hr.loan'].search_count([('employee_id', '=', values['employee_id']), ('state', '=', 'approve'),
('balance_amount', '!=', 0)])
即使balance_amount
等于Zero
您需要在这里做一些事情。
- 定义重新计算依赖性,并使用
@api.multi
和A进行self
循环或使用api.one
并跳过A进行循环。如果我理解您的计算方法正确:
@api.multi
@api.depends('loan_lines.paid', 'loan_lines.amount', 'loan_amount')
def _compute_loan_amount(self):
for loan in self:
total_paid = 0.0
for line in loan.loan_lines:
if line.paid:
total_paid += line.amount
balance_amount = loan.loan_amount - total_paid
loan.total_amount = loan.loan_amount # ???
loan.balance_amount = balance_amount
loan.total_paid_amount = total_paid
尝试使用float舍入例如2个小数,因为浮子可以产生0.000000000000000002之类的值,这会打破您的搜索。
您要么必须存储该值,要么必须定义
search
方法。第二种方法更加困难(根据我的经验(。