一次重命名多个文件

Question

我有一个大量的数据集，这些文件均以这样的命名：

proportional.rank_9.cycle_10157.ratio_9
proportional.rank_9.cycle_10158.ratio_0
proportional.rank_9.cycle_10159.ratio_130
proportional.rank_9.cycle_10160.ratio_7

但是，当然，事后看来这会使文件中的读数很难，因为我需要文件名，并且每个文件的比例可能不同。有没有办法一次重命名所有文件，以使比率_*消失了？

理想情况下，我希望它们以这种形式：

proportional.rank_9.cycle_10157
proportional.rank_9.cycle_10158
proportional.rank_9.cycle_10159
proportional.rank_9.cycle_10160

Answer 1

//set X to all files of the form proportional.rank
X=$(ls proportional.rank*) 
//print out to check X is set
echo $X 
//loop over all files of X
for i in $X ; do
  before_stem=${i%.ratio_*} //what I want to keep
  after_stem=${i#*.ratio_}  //what I don't want
  new_end =$(printf ".out" $after_stem) //give new ending
  mv $i ${before_stem}${new_end} //concatenate the new ending and old beginning
done

％：在遵循％

的模式之前将所有内容

磅标牌：在遵循＃

的模式之后拿走一切

printf：就像c printf

一样

proportional.rank_9.cycle_10157.ratio_9
proportional.rank_9.cycle_10158.ratio_0
proportional.rank_9.cycle_10159.ratio_130
proportional.rank_9.cycle_10160.ratio_7

变成

proportional.rank_9.cycle_10157.out
proportional.rank_9.cycle_10158.out
proportional.rank_9.cycle_10159.out
proportional.rank_9.cycle_10160.out