如何包装API响应以处理基于干净架构的成功和错误

Question

包装服务器响应然后进行处理的方法是什么？API以以下格式返回响应：

成功：

{
"data": [],
"statusCode": 200,
"statusMessage": "Operation success",
"success": true
}

故障：

{
"errors": [],
"statusCode": 500,
"statusMessage": "Something went wrong",
"success": false
}

我正在尝试将Clean Architecture原则应用于我的应用程序，我想知道如何包装响应以更好地处理错误？

Answer 1

1. fillCities((调用getCities(
2. getCities((调用getCityList((

3. getCities通过funcErrorCheckAndTransform处理来自getCityList端点的响应，并返回一个可观察到的呈现层

   fun <T> funcErrorCheckAndTransform(): (BaseResponse<T>) -> Observable<T> {
   return { response ->
   if (response.isSuccess) {
   Observable.just(response.data)
   } else {
   val e = Exception(response.errorMsg)
   Timber.e(e)
   Observable.error(e)
   }
   }
   }
   
   override fun getCities(): Observable<out Cities> {
   return locationService.getCityList()
   .subscribeOn(schedulerProvider.io())
   .flatMap(funcErrorCheckAndTransform())
   .observeOn(schedulerProvider.ui())
   }
   
   @GET("getcitylist")
   fun getCityList():
   Observable<BaseResponse<ProfileResponse.Cities>>
   
   override fun fillCities(defaultCityName: String?) {
   view.showProgress(R.string.cities_are_getting_dialog_message)
   compositeDisposable.add(
   interactor.getCities().subscribe(
   {
   view.hideProgress()
   view.fetchCities(it, defaultCityName)
   },
   { error ->
   view.onError(error)
   }
   ))
   }