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Question

>我有如下所示的字符串

Declare @string ='welcome'

我想要这样的输出

w
e
l
c
o
m
e 

Answer 1

你可以为此使用计数表，通常比循环快，但你必须自己测试：

declare @s varchar(200)
set     @s = 'Welcome'

;with t as (
select  v
from    (values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) t(v)
),
n as (
select  row_number() over(order by (select null)) rn
from    t t1 cross join t t2
)
select  substring(@s, rn, 1)
from    n
where   rn <= len(@s)

Answer 2

DECLARE @string VARCHAR(256) = 'welcome'
DECLARE @cnt INT = 0;
WHILE @cnt < len(@string)
BEGIN
SET @cnt = @cnt + 1;
PRINT SUBSTRING ( @string ,@cnt , 1 )  
END;

实质上，您循环遍历字符串的长度。 在循环索引的位置打印字符并打印该字符。

Answer 3

您可以使用递归 CTE。

Declare @string varchar(10) ='welcome'
;with cte as 
(
select 1 as i,substring(@string,1,1) as single_char
union all
select i+1 as i,convert(varchar(1),substring(@string,i+1,i+1)) as single_char from cte where len(convert(varchar(1),substring(@string,i+1,i+1)))=1
)
select single_char From cte