如何从视图中获取控制器中的数据

Question

我想将数组从视图保存到数据库 但我无法从视图中获取数组。

在视图页面中

<?php
$nilai = array(
array(1,2,3,4),
array(a,b,c,d)
);
<a href="<?= BASEURL; ?>/penerima/tambah?nilai=$nilai" class="btn btn-l btn-info">simpan</a>

在控制器页面中

<?php
class Penerima  extends Controller
{
public function index()
{
$data['penerima'] = $this->model('Penerima_model')->getAll();
$this->view('templates/header');
$this->view('penerima/index', $data);
$this->view('templates/footer');
}
public function tambah() and I'm using MVC concept
{
$nilai = $_GET['nilai'];
$this->model('Penerima_model')->tambahData($nilai);
}
}

我有二维数组。

如何解决此问题？

Answer 1

我找到了解决方案。这是对我有用的。我使用

json_encode()

解决方案是转义字符，所以我不得不将上面的行替换为

htmlspecialchars(json_encode(array))

溶液：

$nilai = array(
array(1,2,3,4),
array('a','b','c','d')
);
<a href="http://localhost/code/tambah?nilai=<?= htmlspecialchars(json_encode($nilai)); ?>" class="btn btn-l btn-info">simpan</a>

在控制器中，我必须使用以下行从 JSON 获取我的数组

function tambah(){
$dataJson = $this->input->get('nilai');
$dataArray = json_decode(htmlspecialchars_decode($dataJson), true);
print_r($dataArray);
}

最佳解决方案

最好的方法是使用会话

$this->session->set_userdata('nilai',$nilai);
<a href="http://localhost/code/tambah" class="btn btn-l btn-info">simpan</a>

现在，进入控制器

function tambah(){
$array = $this->session->userdata('nilai');
}

注意：在控制器中加载会话库或自动加载

Answer 2

查看参考 将数组作为 url 参数传递 如果您正在使用codeigniter framework那么要从 URL 获取值，请尝试使用

$nilai = $this->input->get('nilai');

Answer 3

You can't send array in get request as it is. So you can change your code as shown below

in view page
<?php
$nilai = array(
array(1,2,3,4),
array(a,b,c,d)
);
$nilai = json_encode($nilai);
<a href="<?= BASEURL; ?>/penerima/tambah?nilai=$nilai" class="btn btn-l btn-info">simpan</a>

in controller page
<?php
class Penerima  extends Controller`
{
public function index()
{
$data['penerima'] = $this->model('Penerima_model')->getAll();
$this->view('templates/header');
$this->view('penerima/index', $data);
$this->view('templates/footer');
}
public function tambah()
{
$nilai = $_GET['nilai'];
$nilai = json_decode($nilai);
$this->model('Penerima_model')->tambahData($nilai);
}
}

Answer 4

您可以json_encodearray并使用urlencode传递它。

在您看来：

<?php
$nilai = array(
array(1,2,3,4),
array(a,b,c,d)
);
// encode to json string and encode to valid url
$nilai_urlencoded = urlencode(json_encode($nilai));
?>
<a href="<?= BASEURL; ?>/penerima/tambah?nilai=<?=$nilai_urlencoded; ?>" class="btn btn-l btn-info">simpan</a>

在控制器中，解码json字符串

<?php
class Penerima  extends Controller
{
public function index()
{
$data['penerima'] = $this->model('Penerima_model')->getAll();
$this->view('templates/header');
$this->view('penerima/index', $data);
$this->view('templates/footer');
}
public function tambah()
{
// Decode the url first and then convert the json_string to array
$nilai = json_decode(urldecode($_GET['nilai'])));
$this->model('Penerima_model')->tambahData($nilai);
}
}