在 iOS 中设置时间格式

Question

我从谷歌服务器获得时间PT4M30S,PT7M2S。如果是第一个，即PT4M30S，那么我将其显示为4:30。但是第二个像这样7:2来了，我不想要。我喜欢它像7:02.

这就是我所做的一些

 NSString *m=@"M";                                         
     NSString *s=@"S";
    NSRange rang =[videoTimeString rangeOfString:m options:NSCaseInsensitiveSearch];                 
if(rang.length==[m length])
   {
      if(rang.length==[s length])
    {
      NSString *string1=[videoTimeString stringByReplacingOccurrencesOfString:@"PT" withString:@""];
    NSString *string2=[string1 stringByReplacingOccurrencesOfString:@"M" withString:@":"];
    finalTime=[string2 stringByReplacingOccurrencesOfString:@"S" withString:@""];}
     else{
     NSString *string1=[videoTimeString stringByReplacingOccurrencesOfString:@"PT" withString:@""];
                        finalTime=[string1 stringByReplacingOccurrencesOfString:@"M" withString:@":00"];
                      }
                    }
                else{
                    NSString *string1=[videoTimeString stringByReplacingOccurrencesOfString:@"PT" withString:@"0:"];
                    finalTime=[string1 stringByReplacingOccurrencesOfString:@"S" withString:@""];
    }

因此，任何帮助将不胜感激。

谢谢

Answer 1

下面的方法将获取PT7M2S格式的字符串并将其转换为7:02。

- (NSString *)parseGoogleTime:(NSString *)time
{
    NSError *error = nil;
    NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:@"PT(\d+)M(\d+)S"
                                                                           options:NSRegularExpressionCaseInsensitive
                                                                             error:&error];
    if (error) {
        return nil;
    }
    NSArray *matches = [regex matchesInString:time options:0 range:NSMakeRange(0, time.length)];
    if (matches.count == 0) {
        return nil;
    }
    NSTextCheckingResult *match = matches[0];
    NSMutableString *parsedTime = [NSMutableString string];
    NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];
    [formatter setNumberStyle:NSNumberFormatterDecimalStyle];
    for (NSUInteger i = 1; i < match.numberOfRanges; i++) {
        NSString *substringForMatch = [time substringWithRange:[match rangeAtIndex:i]];
        NSInteger timePart = [[formatter numberFromString:substringForMatch] integerValue];
        [parsedTime appendFormat:i == 1 ? @"%i:" : @"%02i", timePart];
    }
    return parsedTime;
}