是否有可能在Android中执行服务，只有当我有一个特定的应用程序是开放的

Question

是否有办法执行一个服务(启动或停止)只有当一个特定的应用程序是打开的?情况是，我有一个"泡沫"服务(类似于facebook)，我只想在打开游戏Minecraft PE时出现。当我改变或我打开另一个应用程序，我想把隐形泡沫。这可能吗?

Answer 1

使用此代码

public class CheckRunningApplicationReceiver extends BroadcastReceiver {
    @Override
    public void onReceive(Context aContext, Intent anIntent) {
        try {            
            ActivityManager am = (ActivityManager) aContext
                    .getSystemService(Context.ACTIVITY_SERVICE);
            List<ActivityManager.RunningTaskInfo> alltasks = am
                    .getRunningTasks(1);
            for (ActivityManager.RunningTaskInfo aTask : alltasks) {
                if (aTask.topActivity.getClassName().equals("com.android.phone.InCallScreen")
                    || aTask.topActivity.getClassName().equals("com.android.contacts.DialtactsActivity"))
                {
                    Toast.makeText(aContext, "Phone Call Screen.", Toast.LENGTH_LONG).show();   
                }
                String packageName = "com.example.checkcurrentrunningapplication";
                if (aTask.topActivity.getClassName().equals(
                        packageName + ".Main"))
                {
                   // When opens this example screen then show a alert message
                   Toast.makeText(aContext, "Check Current Running Application Example Screen.", 
                                   Toast.LENGTH_LONG).show();   
                }
            }
        } catch (Throwable t) {
            Log.i("THROW", "Throwable caught: "
                        + t.getMessage(), t);
        }
    }
}

将此添加到Manifest:

<receiver android:name = ".CheckRunningApplicationReceiver"/>
<uses-permission android:name="android.permission.GET_TASKS" />