查找带有exec echo选项的命令在文件名中包含./

Question

如何避免在输出中显示前导。/?

实际产出

test@testmachine:/usr/lib$ find . -name "*" -exec echo {} ;
.
./pymodules/python2.7/pyliblzma-0.5.3.egg-info
./pymodules/python2.7/pyliblzma-0.5.3.egg-info/PKG-INFO
./pymodules/python2.7/pyliblzma-0.5.3.egg-info/top_level.txt
./pymodules/python2.7/pyliblzma-0.5.3.egg-info/dependency_links.txt
./pymodules/python2.7/pyliblzma-0.5.3.egg-info/SOURCES.txt

所需输出:

test@testmachine:/usr/lib$ find . -name "*" -exec xxxxxxxxxx ;
pymodules/python2.7/pyliblzma-0.5.3.egg-info
pymodules/python2.7/pyliblzma-0.5.3.egg-info/PKG-INFO
pymodules/python2.7/pyliblzma-0.5.3.egg-info/top_level.txt
pymodules/python2.7/pyliblzma-0.5.3.egg-info/dependency_links.txt
pymodules/python2.7/pyliblzma-0.5.3.egg-info/SOURCES.txt

Answer 1

不要指定.作为搜索目录。

find * -exec echo {} ;

命令的-name '*'部分不会消除以.开头的名称，但是globing会。如果有问题，那么在-exec之前添加.[!.]*(跳过.和..，也跳过..hidden);