ES6:MailChimp API的对象重组

Question

我想在数组和另一个对象上构造一个对象基础。

目标是发送给我的用户兴趣的mailchimp api，因为我得到了：

//Array of skills for one user    
const skillsUser1 = ["SKILL1", "SKILL3"]
//List of all my skills match to mailchimp interest group
const skillsMailchimpId = {
  'SKILL1': 'list_id_1',
  'SKILL2': 'list_id_2',
  'SKILL3': 'list_id_3',
}
//Mapping of user skill to all skills
const outputSkills = skillsUser1.map((skill) => skillsMailchimpId[skill]);
console.log(outputSkills);

问题之后，输出kill给我一个数组：

["ID1", "ID3"]

但是mailchimp api需要什么，所以我需要什么：：

{ "list_id_1": true,
  "list_id_2": false, //or empty
  "list_id_3" : true
}

Answer 1

一种简单的方法就是这样（请参阅代码中的注释）：

// Array of skills for one user    
const skillsUser1 = ["SKILL1", "SKILL3"]
// List of all my skills match to mailchimp interest group
const skillsMailchimpId = {
  'SKILL1': 'list_id_1',
  'SKILL2': 'list_id_2',
  'SKILL3': 'list_id_3',
}
// Create an output object
const outputSkills = {};
// Use `Object.entries` to transform `skillsMailchimpId` to array
Object.entries(skillsMailchimpId)
  // Use `.forEach` to add properties to `outputSkills`
  .forEach(keyValuePair => {
    const [key, val] = keyValuePair;
    outputSkills[val] = skillsUser1.includes(key);
  });
console.log(outputSkills);

基本想法是通过skillsMailchimpId而不是skillsUser循环。

，但这不是很动态。对于您的生产代码，您可能想重构它更灵活。

// Array of skills for one user    
const skillsUser1 = ["SKILL1", "SKILL3"]
// List of all my skills match to mailchimp interest group
const skillsMailchimpId = {
  'SKILL1': 'list_id_1',
  'SKILL2': 'list_id_2',
  'SKILL3': 'list_id_3',
}
// Use `Object.entries` to transform `skillsMailchimpId` to array
const skillsMailchimpIdEntries = Object.entries(skillsMailchimpId);
const parseUserSkills = userSkills => {
  // Create an output object
  const outputSkills = {};
  
  // Use `.forEach` to add properties to `outputSkills`
  skillsMailchimpIdEntries.forEach(([key, val]) => {
    outputSkills[val] = userSkills.includes(key);
  });
  
  return outputSkills;
}
// Now you can use the function with any user
console.log(parseUserSkills(skillsUser1));